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bazaltina [42]
3 years ago
9

Solve the equation x^3-5x^2+2x+8=0 given that -1 is a zero of f(x)=x^3-5x^2+2x+8

Mathematics
1 answer:
liraira [26]3 years ago
3 0
-1^3-5(-1)^2+2(-1)+8
-1-5-2+8
-6-2+8
-8+8=0
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Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g
SpyIntel [72]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see    \bf f(x)=\sqrt{x}\qquad 
\begin{array}{llll}
g(x)=&\sqrt{0.5x}\\
&\quad \uparrow \\
&\quad  B
\end{array}

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.
8 0
3 years ago
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Write the standard form of the equation of the line through the pair of points (6,3) and (-7,7)
timofeeve [1]

Step-by-step explanation:

steps are in the picture above.

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3 0
3 years ago
A patio in the shape of a semicircle has a diameter of 21 ft.
nikklg [1K]
The answer is 173 ft²

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A = A1/2

The area of the circle with radius r is: 
A1 = π * r²
π = 3.14
We do not have the radius, but we know that it is a half of the diameter:
r = 21 ft / 2 = 10.5 ft

A1 = 3.14 * (10.5)² = 346.18 ft²

So, the area of the patio is:
A = A1/2
A = 346.18 ft² / 2
A = 173.09 ft² ≈ 173 ft²
3 0
3 years ago
Which properties justify the steps taken to solve the system? {3x−4y=9 2x+8y=6 Drag the answers into the boxes to match each ste
anzhelika [568]
1.) 6x-8y=18, 2x+8y=6 → Multiplication property of equality

2.) 8x=24 → Addition property of equality

3.) x=3 → Division property of equality

4.) 3(3)-4y=9 → Substitution property of equality

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4 0
3 years ago
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An office has 150 employees, and 30 of the employees work the night shift. What percentage of the employees work the night shift
Zanzabum
<h2>Answer:</h2>

The percent of employees who work in the night shift are:

                                     20%

<h2>Step-by-step explanation:</h2>

Total number of employee in the office are: 150

Number of employee who work in the night shift are:  30

The percent of the employee who work in the night shift is calculated as follows:

\dfrac{\text{Number\ of\ people\ working\ in\ the\ night\ shift}}{\text{Total\ number\ of\ employees}}\times 100

Hence, on putting the value in the above formula we get:

=\dfrac{30}{150}\times 100\\\\\\=\dfrac{1}{5}\times 100\\\\\\=20\%

            Hence, the answer is:

                          20%

4 0
3 years ago
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