Solve the equation x^3-5x^2+2x+8=0 given that -1 is a zero of f(x)=x^3-5x^2+2x+8

Mathematics

1 answer:

liraira [26]3 years ago

3 0

-1^3-5(-1)^2+2(-1)+8
-1-5-2+8
-6-2+8
-8+8=0

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<img src="https://tex.z-dn.net/?f=4%20%5Ctimes%208%20%5E%7B2x%20%2B%201%3F%7D%20%20%3D%2032%20%5E%7Bx%20%2B%202%7D%20" id="TexFo

svet-max [94.6K]

Answer:

x = 5

Step-by-step explanation:

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FACTS TO KNOW BEFORE SOLVING :-

$a^x \times a^y = a^{x+y}$

In an equation , if the bases are same in both L.H.S. & R.H.S. then , the power of the bases on both the sides of equation should be equal. For e.g. : $a^x = a^y$ ⇒ $x = y$ [∵ Bases are equal on both the sides]