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alexandr402 [8]
2 years ago
15

For times t> 0 in seconds, a superhero's height above the ground in meters is given by the function

Mathematics
1 answer:
hram777 [196]2 years ago
6 0

Answer:

NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by

Assuming rocket launched at t = 0 and height is measured above sea level in meters.

Step-by-step explanation:

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Subtract.<br> (6x + 5) - (x+3)
Roman55 [17]

(6x+5)-(x+3).

6x+5-x-3.

Add the like terms.

6x-x+5-3.

We get.

5x+2.

6 0
3 years ago
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Solve the equation and explain each step using apropriate Properties<br> -4(3x+6)+6=-30
Lina20 [59]

Answer:

The answer is x=1

Step-by-step explanation:

-4(3x+6)+6=-30

-12x-24+6=-30

-12x-18=-30

-12x-18+18=-30+18

-12x=-12

-12x/-12=-12/-12

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2 years ago
You bought 7 raffle tickets. A total of 1302 raffle tickets were sold. If every raffle ticket has an equal chance at winning, wh
gayaneshka [121]

Answer:

the probability of not winning is 0.9946

Step-by-step explanation:

The computation of the probability of not winning is shown below:

The Probability of winning is

= 7 ÷ 1302

So, the probability of not winning is

= 1 - 7 ÷ 1302

= (1302 - 7) ÷ 1302

= 1295 ÷ 1302

= 165 ÷ 186

= 0.9946

Hence, the probability of not winning is 0.9946

The same is considered

6 0
3 years ago
A new car is purchased for 22400 dollars. The value of the car depreciates at 11% per year. To the nearest tenth of a year , how
m_a_m_a [10]

Answer:

t= 12.9 years

Step-by-step explanation:

Value after t years = initial value ( 1 - r )^t

Where,

Value after t years= $5000

Initial value = $22,400

r= depreciation rate = 11%

t= length of time (years)

Value after t years = initial value ( 1 - r )^t

5000 = 22,400 ( 1 - 0.11)^t

5000 = 22,400(0.89)^t

Divide both sides by 22,400

(0.89)^t = 5000 / 22,400

(0.89)^t = 0.2232

Take the log of both sides

t log 0.89 = log 0.2232

t= log 0.2232 / log 0.89

= -0.6513 / -0.0506

= 12.87

t= 12.9 years

5 0
3 years ago
Can someone please help me
zhuklara [117]
So what is the question?
7 0
2 years ago
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