Check the picture below.
A)
well, we start off by making a table of values for the function, with a few "t" values, as you see in the picture, then graph those points to get the graph.
B)
at t = 0, h(0) = 98, and at t = 1, h(1) = 82, so it went from 98 to 82, for a difference of 16.
C)
at t = 1, h(1) = 82, and at t = 2 h(2) = 34, so it went from 82 to 34, for a difference of 48.
does it fall the same distance on both intervals? well, they're different, so nope.
Subtract 70 from 16, and you get 54.
Answer:
The top option is false.
Step-by-step explanation:
Both segments have a <em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>] of ⅔. It just that their ratios have unique qualities:

Greatest Common Factor: 2
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<em>BC</em><em> </em>is at a 4⁄6 slope, and <em>AB</em><em> </em>is at a ⅔ slope. Although their quantities are unique, they have the exact same value.
I am joyous to assist you anytime.
Answer:
Answer is BD
Step-by-step explanation: