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3 years ago

Help me with this please

Mathematics

2 answers:

Westkost [7]3 years ago

8 0

( 2,-1) that should be your answer! :)

Airida [17]3 years ago

5 0

Answer: (2,-1)

Midpoint formula = ( $\frac{x1+x2}{2}$ , $\frac{y1+y2}{2}$ )

9 + (-5) / 2 = 2

3 + (-5) / 2 = -1

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serg [7]

Answer:

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4 0

3 years ago

Given the trinomial 3x2 − 6x + 5, what is the value of the discriminant?

yan [13]

$\bf \begin{array}{llcccll}
& 3 x^2& -6 x& +5\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}
\\\\\\
discriminant\implies b^2-4ac\implies (-6)^2-4(3)(5)$

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3 years ago

What is the distance between the points (1, -4) and (1, 0)

tino4ka555 [31]

For this case we have that the distance between two points is given by:

$d = \sqrt{(y2-y1)^2+(x2-x1)^2}$

Given the points:

$(x1, y1) = (1, -4)(x2, y2) = (1,0)$

We substitute in the formula:

$d = \sqrt{(0 - (- 4)) ^ 2 + (1-1) ^ 2}$

$d = \sqrt{(4 ^ 2 + 0 ^ 2)}$

$d=\sqrt{16}$

$d = 4$

So, the distance is $d = 4$

Answer:

$d = 4$

5 0

3 years ago

Need help finding the area of the shaded region

abruzzese [7]

Check the picture below, the assumption being that the 6ft line is perpendicular to the 18ft line and thus making a right-triangle.

now, if we just get the whole area of the containing parallelogram and then <u>get the area of the triangle and subtract it from that of the parallelogram's,</u> what's leftover is the area we didn't subtract, the shadead area.

$\stackrel{ \textit{\LARGE Areas}}{\stackrel{parallelogram}{(18)(10)}~~ - ~~\stackrel{triangle}{\cfrac{1}{2}(18)(6)}}\implies 180~~ - ~~54\implies 126$

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2 years ago

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Llana [10]

First, notice that we are given the y-intercept, (0, 5), and the slope, m = 7.

We plug into slope-intercept form $y=mx+b$ to get $y=7x+5$ .

5 0

4 years ago

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