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BabaBlast [244]
2 years ago
11

HELPPPP PLEASEEEE

Chemistry
1 answer:
Rama09 [41]2 years ago
6 0

1.025 moles of NaCl are present in a solution with a molarity of 8.20M and 125 mL of solution. Details about molarity can be found below.

<h3>How to calculate molarity?</h3>

The number of moles of a solution can be calculated by multiplying the molarity of the solution by its volume. That is;

no of moles = molarity × volume

According to this question, a solution has a molarity of 8.20M and volume of 125 mL of solution.

no of moles = 8.20 × 0.125

no of moles = 1.025moles

Therefore, 1.025 moles of NaCl are present in a solution with a molarity of 8.20M and 125 mL of solution.

Learn more about number of moles at: brainly.com/question/14919968

#SPJ1

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<u>Answer:</u> The molarity of NO_3^- ions in the solution is 0.306 M

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of solute (Cu(NO_3)_2.6H_2O) = 15.6 g

Molar mass of (Cu(NO_3)_2.6H_2O) = 295.6 g/mol

Volume of solution = 345 mL

Putting values in above equation, we get:

\text{Molarity of }Cu(NO_3)_2.6H_2O=\frac{15.6g\times 1000}{295.6g/mol\times 345mL}\\\\\text{Molarity of }Cu(NO_3)_.6H_2O=0.153M

As, 1 mole of (Cu(NO_3)_2.6H_2O) produces 1 mole of copper (II) ions and 2 moles of nitrate ions.

So, molarity of NO_3^- ions = (2 × 0.153) = 0.306 M

Hence, the molarity of NO_3^- ions in the solution is 0.306 M

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