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Sedaia [141]
3 years ago
11

Which of the following is not a correct formula? A)Ba2O B)Ca3N2 C)KCl D)Li2S

Chemistry
1 answer:
love history [14]3 years ago
7 0

Answer:- A. Ba_2O is not the correct formula.

Explanations:- Charge for Ba is +2 and charge for O is -2, Here the charges are in equal and opposite so their ratio is 1:1 and hence the formula must be BaO and not Ba_2O.

Rest of the formulas are correct as charge for Ca is +2 and charge for N is -3 . On criss cross we get the formula Ca_3N_2 .

Charge for K is +1 and charge for Cl is -1 and so KCl is correct.

Charge for Li is +1 and that for S is -2. On criss cross we get the formula Li_2S .

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In the equation N2(g) + 3H2(g)--- 2NH3(g), how many liters of hydrogen
Delicious77 [7]

Answer:

30 L H2

Explanation:

  • 10 L N2 x <u>3 L H2</u> = 30 L H2

.                         1 L N2

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What are green boxes on periodic tables
finlep [7]

Answer:

The basic metal ones?

Explanation:

...

3 0
3 years ago
Given that ΔH = −571.6 kJ/mol for the reaction 2 H2(g) + O2(g) → 2 H2O(l), calculate ΔH for these reactions. (a) 2 H2O(l) → 2 H2
pashok25 [27]

Answer : The value of \Delta H for the reaction is +571.6 kJ/mole.

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction is,

2H_2(g)+O_2(g)\rightarrow 2H_2O(l)     \Delta H_1=-571.6kJ/mole

Now we have to determine the value of \Delta H for the following reaction i.e,

2H_2O(l)\rightarrow 2H_2(g)+O_2(g)    \Delta H_2=?

According to the Hess’s law, if we reverse the reaction then the sign of \Delta H change.

So, the value \Delta H_2 for the reaction will be:

\Delta H_2=-(-571.6kJ/mole)

\Delta H_2=+571.6kJ/mole

Hence, the value of \Delta H for the reaction is +571.6 kJ/mole.

6 0
3 years ago
For the reaction below, complete the rate expression that relates the change in concentration with respect to time to the rate o
Ann [662]

Answer: Rate in terms of disappearance of NO = -\frac{1d[NO]}{2dt}

Rate in terms of disappearance of Cl_2= -\frac{1d[Cl_2]}{1dt}

Rate in terms of appearance of NOCl = \frac{1d[NOCl]}{2dt}

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

2NO+Cl_2\rightarrow 2NOCl

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of  = -\frac{1d[NO]}{2dt}

Rate in terms of disappearance of = -\frac{1d[Cl_2]}{1dt}

Rate in terms of appearance of NOCl = +\frac{1d[NOCl]}{2dt}

5 0
3 years ago
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