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Sedaia [141]
3 years ago
11

Which of the following is not a correct formula? A)Ba2O B)Ca3N2 C)KCl D)Li2S

Chemistry
1 answer:
love history [14]3 years ago
7 0

Answer:- A. Ba_2O is not the correct formula.

Explanations:- Charge for Ba is +2 and charge for O is -2, Here the charges are in equal and opposite so their ratio is 1:1 and hence the formula must be BaO and not Ba_2O.

Rest of the formulas are correct as charge for Ca is +2 and charge for N is -3 . On criss cross we get the formula Ca_3N_2 .

Charge for K is +1 and charge for Cl is -1 and so KCl is correct.

Charge for Li is +1 and that for S is -2. On criss cross we get the formula Li_2S .

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Bari oxit có công thức hóa hóa học là BaO . vậy bari oxit được tạo nên từ các nguyên tố
Softa [21]

Answer:

Bari oxit được tạo nên từ các nguyên tố Bari (Ba) và Oxi (O)

Explanation:

6 0
2 years ago
Elements that have atoms with stable valence electron configurations in the ground state are found in
dsp73

Answer:

Group 18, also known as the Noble Gasses

Explanation:

Atoms strive for full stability by gaining or losing electrons to get 8 valence electrons in their valence shell, but Group 18 already has 8 electrons in their valence shell, and are therefore already stable in their ground state.

5 0
3 years ago
What is the total mass of solute in 1000. grams of a solution having a concentration of 5 parts per million?
Art [367]

50 grams or 50,000 mili grams  is the mass of solute in 1000 grams of a solution having a concentration of 5 parts per million.

Explanation:

Total mass of solution = 1000 grams or 1000 ml since 1 gram = 1 ml

concentration is 5 parts per million ( 5 mg in 1000 ml solution or 0.005 gram in 1000 ml)

the formula used for parts per million:

parts per million = \frac{mass of solute (mg)}{volume of solution}

putting the values in the equation:

parts per million = \frac{mass of solute}{volume of solvent}

0.005 x 1000 = mass of solute

50 grams= mass of solute

converting this into mg

50,000 mg. is the total mass of solute in 5ppm of 1000 ml solution.

4 0
3 years ago
What term refers to rows of elements
qaws [65]
Period are going left to right across the periodic table
Groups are going up to down on the periodic table
3 0
3 years ago
Read 2 more answers
600 s after initiation of a first order reaction 48.5% of the initial reactant concentration remains present. What is the rate c
Ludmilka [50]

Answer:

k=1.20x10^{-3} s^{-1}

Explanation:

For a first order reaction the rate law is:

v=\frac{-d[A]}{[A]}=k[A]

Integranting both sides of the equation we get:

\int\limits^a_b {\frac{d[A]}{[A]}} \, dx =-k\int\limits^t_0 {} \, dt

where "a" stands for [A] (molar concentration of a given reagent) and "b" is {A]0 (initial molar concentration of a given reagent), "t" is the time in seconds.

From that integral we get the integrated rate law:

ln\frac{[A]}{[A]_{0} } =-kt

[A]=[A]_{0}e^{-kt}

ln[A]=ln[A]_{0} -kt

k=\frac{ln[A]_{0}-ln[A]}{t}

therefore k is

k=\frac{ln1-ln0,485}{600}=1,20x10^{-3}

8 0
4 years ago
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