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liq [111]
4 years ago
15

PLZ HELP When subjected to heat and pressure, a chemical sedimentary rock can be changed into which rock type?

Chemistry
2 answers:
vlada-n [284]4 years ago
7 0
A metamorphic rock.....
tresset_1 [31]4 years ago
7 0

B. Metamorphic rock

:)

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If the outside of your flask is not dry when the first mass determination is made and it is dried for the second mass determinat
svlad2 [7]

Answer:

You'll experience a grater deviation

Explanation:

<em>You'll experience a greater deviation in your measurements, meaning your measures will have a bigger difference between them, and the greater these deviations the less accurate will be the measuring.</em> This happens mainly because you're not replicating the measurement with the exact same conditions, in one of them you'll have an extra mass from the water.

I hope you find this information useful and interesting! Good luck!

8 0
3 years ago
Check my answers please? Only 5...Will reward medal to best answer and perhaps become a fan! :)
stellarik [79]
The correct answer is <span>Fusion Curve</span>
5 0
3 years ago
What is the difference between acute and chronic radiation poisoning
otez555 [7]
Acute: Can be repaired by the body using white blood cells.

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4 0
4 years ago
PLEASE HELPPPP!!! IM BEING TIMED
Mrac [35]

Answer:

B)

Explanation:

This should be the correct answer, lmk if it's not

8 0
3 years ago
Read 2 more answers
. In which reaction is nitric acid acting as an oxidising agent?
Talja [164]

Answer:

B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2

Explanation:

Hello,

In this case, we should understand oxidizing agents as those substances able to increase the oxidation state of another substance, therefore, in B. reaction we notice that copper oxidation state at the beginning is zero (no bonds are formed) and once it reacts with nitric acid, its oxidation states raises to +2 in copper (II) nitrate, thus, in B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2 nitritc acid is acting as the oxidizing agent.

Moreover, in the other reactions, copper (A.), sodium (C. and D.) remain with the same initial oxidation state, +2 and +1 respectively.

Regards.

8 0
3 years ago
Read 2 more answers
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