Answer:
P₂ = 3.61 atm
Explanation:
Given data:
Initial pressure of tank = 3.20 atm
Initial temperature = 22.0°C
Final temperature = 60.0°C
Final pressure = ?
Solution:
Initial temperature = 22.0°C (22.0 +273 = 295 K)
Final temperature = 60.0°C (60 +273 = 333)
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
3.20 atm / 295 K = P₂/333 K
P₂ = 3.20 atm × 333 K / 295 K
P₂ = 1065.6 atm. K /295 K
P₂ = 3.61 atm
