The period of
is
.
Recall that
and
both have periods of
. This means


Replacing
with
, we have

In other words, if we change
by some multiple of
, we end up with the same output. So
has period
.
Similarly,
has a period of
,

We want to find the period
of
, such that


On the left side, we have

and

So, in terms of its period, we have

and we need to find the smallest positive
such that

which points to
, since


Answer:
5.76 rounded to the nearest tenth is 5.8 or 5.80.
Answer:
x will equal 6.25
Step-by-step explanation:
all you have to do is divide both sides by 8
Answer:
44
Step-by-step explanation:
Let x and y be the total number of questions in part 1 and part 2 exams respectively.
For part 1:
Number of correct question = 4/5 of the total number of question in part 1


For part 2:
Number of corrected question = 2/3 of total number of question in part 2


So, the total umbers of the questions on Stephanie's exam
=x+y
=20+24
=44
Hence, the total umbers of the questions on Stephanie's exam was 44.
Y=3x-14 or 3x-14=Y
This is because you want to keep y positive, and so you add Y on both sides and get 3x=14+y, then you want to get y alone so you subtract 14 on both sides and get 3x-14=Y