Answer:
6 divided by 3/5 is 10
Step-by-step explanation:
I don't know how to do the number line, sorry.
The correct simplification of the expression is 9c^2 i think.
Given the figure of a regular pyramid
The base of the pyramid is a hexagon with a side length = 6
The lateral area is 6 times the area of one of the side triangles
So, the side triangle has a base = 6
The height will be:
![\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D6%5E2%2B%28%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%5Ccdot6%29%5E2%3D36%2B27%3D63%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B63%7D%20%5Cend%7Bgathered%7D)
so, the lateral area =
Answer:
Explanation:
You can convert the percent markup into a multiplicative factor in this way:
Base price: 15,800 . . . (cost to the seller)
Percent mark up: 115% . . . (based on the cost to the seller)
Sale price: 15,800 + 115% of x = 15,800 + 115 × 15,800 /100 =
= 15,800 + 1.15 × 15,800 = 15,800 (2.15) = 33,970
The markup is:
- Markup = price paid by the seller - cost to the seller = 33,970 - 15,800 = 18,170 (notice that this is 115% of 15,800)
And <em>the percent markup based on the sale price is</em>:
- % = (markup / sale price) × 100 = (18,700 / 33,970) × 100 =
= 53.49 %
Rounding to the nearest tenth percent that is 53.5 %.