Answer:
Step-by-step explanation:
A function is odd if f(-x) = -f(x)
A function is even if f(-x) = f(x)
And neither if neither are true.
In this case if we plugged in a negative x here
f(-x) = (-x)^3 - 11(-x)
f(-x) = -x^3 + 11
Therefore, this function is odd because if we pulled out a negative one again we would get back the original function. Or in other words f(-x) = -f(x) for f(x) = x^3 - 11x
Answer:
<u>It is assumed the question is asking to simplify or factorize:</u>
- (a + b)² - a² + b² =
- a² + 2ab + b² - a² + b² =
- 2b² + 2ab
This is simplified expression.
<u>Factorizing as follows:</u>
Answer:
It is a function!
Step-by-step explanation:
It wouldnt be a funtion if the arrows pointed to the same number hope this helps!:)
So, obviously, since one of the prices is given, which is $2.00 for the kid's meal, then you need to subtract that from his $32.00 total to know what number you need to divide into the 6 sandwiches. So, so far you have $30.00. If you divide $30.00 by the 6 sandwiches, you will find out he could only spend $5.00 per sandwich. So basically, you got the expression of (32 -2) / 6 in order to find out that your answer is $5.00. Looking at you answer choices, I can see right away that D is correct. For the inequality, I can see that B would be the correct answer for this problem because he can't go over budget. So, your answers are B and D.
Hope this helps have a nice day and a brainlylist would be appreciated
Answer:

Step-by-step explanation:
We will be using the Law of Sines to find edges <em>b</em> and <em>a</em> one at a time, therefore we will use the given variables in the formulas:
<em>Solving for </em><em>Angles</em>:

**Use
in your solution or you will throw the result off!
<em>Solving for </em><em>Edges</em>:

__________________________________________________________

We will now define edge <em>a</em>:

This triangle is now deemed solved.
***The fact that you solved for the
tells me that you understood what to when it comes to the <em>interior angles of triangles</em>, so I did not have to cover that. Good wourk citisen!
I am delighted to assist you at any time. If you have further questions though, comment them and I will do my very best to answer them.