Solve each proportion. 9/8 = x/7

On another map the distance between saugerties and kingston is 2 inches. Whar would tge distance from saugerties to catskill be

Mariana [72]

The question is incomplete. The map is attached as a photo and here is the complete question:

a. What is the actual distance between Saugerties and

Kingston? ___________________________

b. Catskill is 15 miles from Saugerties. What would the

distance on the map be? ___________________________

c. On another map, the distance between Saugerties and

Kingston is 2 inches. What would the distance from Saugerties to

Catskill be on this map? __________________

Since you have asked the answer for part (c) only, here is the answer:

Answer:

The distance from Saugerties to Catskill would be 3 inches on this map.

Step-by-step explanation:

On the given map, the distance between Saugerties and Kingston is 4 inches and the scale is 1 inch = 2.5 miles.

To calculate the actual distance in miles between Saugerties and Kingston, consider the given scale:

1 inch ---------- 2.5 miles

4 inches ------ x miles

Cross multiplying:

1x = 2.5 x 4

x = 10 miles

The actual distance between Saugerties and Kingston is 10 miles.

On another map, the distance between Saugerties and Kingston is 2 inches. Which means the scale is 2 inches = 10 miles. So 1 inch = 10/2 = 5 miles

The scale on the other map is 1 inch = 5 miles.

Catskill is 15 miles from Saugerties (given in the previous part). So on the map:

1 inch -------- 5 miles

y inch ------- 15 miles

Cross multiplying:

15 = 5y

y = 15/5

y = 3 inches.

The distance from Saugerties to Catskill would be 3 inches on this map.

7 0

3 years ago

PLZ HELP!!!!!!35. ABCD is an isosceles trapezoid with A(0,-1), B(-2,3) and C(6,-1). Find the coordinates of C.

sashaice [31]

Answer:

wouldnt it be (6,-1)...

Step-by-step explanation:

because those are the cords your said c was at

6 0

3 years ago

Cards are selected from a standard deck of 52, the results are recorded in the table. what is the empirical probability of not s

Cerrena [4.2K]

The table have the following results:

Hearts – 7

Diamonds – 4

Clubs – 8

Spades – 5

There is a total of 24

The question is asking for the probability of not selecting a heart.

So we need to add the probabilities of the diamonds, clubs, and spades since these suits are different from hearts.

So = 4 + 8 + 5 = 17

And we have a total of 24 cards

Therefore the probability is 17/24.

7 0

3 years ago

Desperate Please Hurry Question down below

VladimirAG [237]

Answer:

See below

Step-by-step explanation:

I'm guessing you want to fill in the blanks of the sequence?

We can represent this as an equation:

31-3x=18

-3x=13

x=-13/3

Second term: 31 - (13/3) = 26 2/3

Third term: 26 2/3 - (13/3) = 22 1/3

4 0

3 years ago

A life insurance company sells a $100,000 one year term life insurance policy to a 30-year old male for $475. The probability th

laila [671]

Answer:

The expected value for the insurance company is $392.20.

Step-by-step explanation:

The expected value of a random variable, X is:

$E(X)=x\cdot P(X)$

It is provided that a life insurance company sells a $100,000 one year term life insurance policy to a 30-year old male for $475.

The probability that the male survives the year is, P(S) = 0.999172.

Then the probability that the male does not survives the year is:

P (S') = 1 - P (S)

= 1 - 0.999172

P (S') = 0.000828

The amount the company owes the male if he survives is, S = $475.

The amount the company owes the male if he does not survives is,

S' = $475 - $100,000 = -$99525.

Compute the expected value for the insurance company as follows:

$E(\text{Insurance Company})=S\cdot P(S)+S'\cdot P(S')$

$=(475\times 0.999172)+(-99525\times 0.000828)\\=474.6067-82.4067\\=392.20$

Thus, the expected value for the insurance company is $392.20.

4 0

3 years ago