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3 years ago

Find the product ( 6x+4)^2

Mathematics

2 answers:

topjm [15]3 years ago

7 0

(6x + 4) * (6x + 4)
= 36x^2+ 24x + 24x + 16
= 36x^2 + 48x + 16

Sophie [7]3 years ago

3 0

The answer should be 22. hope that helps.

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Marie's journal is 400 pages long. She has used 20% of the journal. How many pages has she used so far?

vitfil [10]

Answer:

40/ or /80

Step-by-step explanation:

Because 400 is a lot and if it's 100% is 400 right so we do 80% what would that be? we don't know right.

What about 100 pages that would be (im pretty sure) 40% or 50%.

I hope this helped!!!

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3 years ago

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Write the equation in standard form. y=4/7x+3

sdas [7]

Answer:

4x-7y = -21

Step-by-step explanation:

1. Move 4/7x to the other side

-4/7x+y=-3

2. Multiply both sides by -7

4x-7y=-21

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3 years ago

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Which expression is equivalent to .02m(n - 5) - .02(m + 10)? A) .02mn - .12m - 0.2 B) .02mn + .12m - 0.2 C) .02mn - .12m + 0.2 D

VikaD [51]

The correct answer is A)<span>.02m(n - 5) - .02(m + 10)</span>

7 0

3 years ago

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A blueprint for a house shows the height of the house to be 3 3/8 inches. The actual house is 21 1/3 feet tall. What is the unit

Amanda [17]

6.32ft per inch (rounded to the hundredth place).

You can get this number by dividing the total number of feet by the total number of inches

6 0

4 years ago

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

5 0

3 years ago