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Semmy [17]
2 years ago
9

In the figure to the right, if AC=12 and BC=9, what is the radius?

Mathematics
1 answer:
ella [17]2 years ago
5 0

Answer:

1

Step-by-step explanation:

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Angle M has a measure between 0° and 360° and is coterminal with a –620° angle. What is the measure of angle M?
OleMash [197]

Answer:

100 or A

Step-by-step explanation:

i hope this is what you were looking for ;)

7 0
2 years ago
An object is launched directly in the air at a speed of 48 feet per second from a platform located 12 feet above the ground. The
anastassius [24]

9514 1404 393

Answer:

  48 ft

Step-by-step explanation:

For the quadratic ax^2 +bx +c, the axis of symmetry is x = -b/(2a). For the given quadratic, which defines a parabola opening downward, the axis of symmetry defines the time at which the maximum height is reached.

  t = -48/(2(-16)) = 1.5

Then the maximum height is ...

  f(1.5) = (-16·1.5 +48)1.5 +12 = (24·1.5) +12

  f(1.5) = 48

The maximum height the object will reach is 48 feet.

6 0
2 years ago
A lake polluted by bacteria is treated with an antibacterial chemical. Aftertdays, thenumber N of bacteria per milliliter of wat
jeyben [28]

Answer:

N(1)=50 is a minimum

N(15)=4391.7 is a maximum

Step-by-step explanation:

<u>Extrema values of functions </u>

If the first and second derivative of a function f exists, then f'(a)=0 will produce values for a called critical points. If a is a critical point and f''(a) is negative, then x=a is a local maximum, if f''(a) is positive, then x=a is a local minimum.  

We are given a function (corrected)

N(t) = 20(t^2-lnt^2)+ 30

N(t) = 20(t^2-2lnt)+ 30

(a)

First, we take its derivative

N'(t) = 20(2t-\frac{2}{t})

Solve N'(t)=0

20(2t-\frac{2}{t})=0

Simplifying

2t^2-2=0

Solving for t

t=1\ ,t=-1

Only t=1 belongs to the valid interval 1\leqslant t\leqslant 15

Taking the second derivative

N''(t) = 20(2+\frac{2}{t^2})

Which is always positive, so t=1 is a minimum

(b)

N(1)=20(1^2-2ln1)+ 30

N(1)=50 is a minimum

(c) Since no local maximum can be found, we test for the endpoints. t=1 was already determined as a minimum, we take t=15

(d)

N(15)=20(15^2-2ln15)+ 30

N(15)=4391.7 is a maximum

7 0
3 years ago
What conclusion can be determined from the dot plot below?
Evgen [1.6K]
The number of observations is 15
3 0
3 years ago
Read 2 more answers
Help with my algebra homework
Maru [420]

Let's solve your equation step-by-step.

2x /5 + 3 = x/10 - 1

Step 1: Simplify both sides of the equation.

2x /5 + 3 =  x/10 - 1

2/5x + 3 = 1/10x - 1

Step 2: Subtract 1/10x from both sides.

2/5x + 3 - 1/10x = 1/10x - 1 - 1/10x

3/10x + 3 = -1

Step 3: Subtract 3 from both sides.

3 /10x + 3 - 3 = -1 - 3

3/10x = -4

Step 4: Multiply both sides by 10/3.

(10/3) * (3/10x) = (10/3) * (-4)

x = -40/3

3 0
3 years ago
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