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Oliga [24]
2 years ago
15

Marc is creating a physical design, what aspect of the design deals with the interaction between a user and data?

Computers and Technology
1 answer:
serious [3.7K]2 years ago
4 0

Answer:

C. User data design

Explanation:

Interaction design can be understood in simple (but not simplified) terms: it is the design of the interaction between users and products. Most often when people talk about interaction design, the products tend to be software products like apps or websites.

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What types of actions exist in activity diagrams?<br>​
iragen [17]

Answer:

Activity Diagrams

Activity. An activity diagram illustrates one individual activity. ...

Action. ...

Calling an Activity (Action) ...

Accepting an Event (Action) ...

Accepting a Time Event (Action) ...

Sending Signals (Action) ...

Edge (Control Flow) ...

Decision Node.

Explanation:

8 0
3 years ago
Write an algorithm to sum to values
Elis [28]

Answer:

There is no need to make an algorithm for this simple problem. Just add the two numbers by storing in two different variables as follows:

Let a,b be two numbers.

c=a+b;

print(c);

But, if you want to find the sum of more numbers, you can use any loop like for, while or do-while as follows:

Let a be the variable where the input numbers are stored.

while(f==1)

{

printf(“Enter number”);

scanf(“Take number into the variable a”);

sum=sum+a;

printf(“Do you want to enter more numbers? 1 for yes, 0 for no”);

scanf(“Take the input into the variable f”);

}

print(Sum)

Explanation:

hi there answer is given mar me as brainliest

5 0
3 years ago
What is 8 hours, 5 minutes, 22 seconds minus (-) 7 hours, 24 minutes, 37 seconds?
olga_2 [115]

Answer:

Enter time 1 HH:MM:SS8:5:22                                                                                                    

Enter time 2 HH:MM:SS7:24:37                                                                                                  

0:40:45

Explanation:

The program for above in Python is:

from datetime import datetime

s1 = input("Enter time 1 HH:MM:SS")

s2 = input("Enter time 2 HH:MM:SS")

Format1 = '%H:%M:%S'

tdiff = datetime.strptime(s1, Format1) - datetime.strptime(s2, Format1)

print(tdiff)

We are using the datetime class in datetime module for using strptime to find the difference between the two times.

3 0
4 years ago
Sara is a college student studying accounting. She uses a laptop daily for personal and course work. What data might Sara have o
polet [3.4K]

Answer:

Sara: Personal data

Jorge : Personal data + official data.

Wanda: Personal data + students data

Carl: Personal data + official data

Explanation:

Personal data could contain pictures, social security numbers, banking transactions details, passwords, credit card information etc.

Jorge's official data could contain information about various sources that he gets his news from. It could contain password information about his official email. And he connects to the office network, he might pose a threat to the entire network if his PC is infected.

Wanda could leak the student's information. She could also leak her social security numbers, bank details, organization's details etc.

Carl could leak company's information. He can avoid it by staying away from public networks. Installing anti-virus. He should also take great care while accessing various sites and never download harmful files over the internet.

8 0
3 years ago
Give an example of an operationin a programming languagethat is implemented.
Shtirlitz [24]

answer:  

(i) #include <iostream>  

using namespace std;  

int main() {  

int n1,n2,max;  

cin>>n1>>n2;  

if(n1>n2)//finding maximum between n1 and n2 in the program directly.  

max=n1;  

else  

max=n2;  

cout<<max;  

return 0;  

}  

(ii)  

#include <iostream>  

using namespace std;  

int maximum(int n1 ,int n2)  

{  

if(n1>n2)//finding maximum between n1 and n2 using function.  

return n1;  

else  

return n2;  

}  

int main() {  

int n1,n2,max;  

cin>>n1>>n2;  

max=maximum(n1,n2);  

cout<<max;  

return 0;  

}  

(iii)  

#include <iostream>  

using namespace std;  

inline int maximum(int n1 ,int n2)  

{  

return (n1>n2)? n1:n2;  

}  

int main() {  

int n1,n2,max;  

cin>>n1>>n2;  

max=maximum(n1,n2);//Finding maximum using inline function.  

cout<<max;  

return 0;  

}  

Output:-  

54 78  

78  

all three codes give the same output.  

Explanation:  

In part (i) I have done the operation in the main function directly.  

In part(ii) I have used function to calculate the maximum.  

In part(iii) I have used inline function to calculate maximum.  

4 0
3 years ago
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