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Lemur [1.5K]
3 years ago
11

Write an algorithm to sum to values

Computers and Technology
1 answer:
Elis [28]3 years ago
5 0

Answer:

There is no need to make an algorithm for this simple problem. Just add the two numbers by storing in two different variables as follows:

Let a,b be two numbers.

c=a+b;

print(c);

But, if you want to find the sum of more numbers, you can use any loop like for, while or do-while as follows:

Let a be the variable where the input numbers are stored.

while(f==1)

{

printf(“Enter number”);

scanf(“Take number into the variable a”);

sum=sum+a;

printf(“Do you want to enter more numbers? 1 for yes, 0 for no”);

scanf(“Take the input into the variable f”);

}

print(Sum)

Explanation:

hi there answer is given mar me as brainliest

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Programming challenge description: Given a string comprising just of the characters (,),{,},[,] determine if it is well-formed o
nadezda [96]

Answer:

Employing Java language,

Explanation:

//for using stack data structure

import java.util.Stack;

//class definition

public class BracketMatch {

   //function to find the string is well formed or not

   public static boolean isWellFormed(String str) {

       //variable to store the character value

       char ch;

       //check if the first character itself is the end of the brackets

       if (str.charAt(0) == ')'||str.charAt(0) =='}'||str.charAt(0) ==']')

           return false;

       //creating a stack of character type

       Stack<Character> stack = new Stack<Character>();

       //iterating through the characters in string

       for(int i=0; i < str.length(); i++) {

           //storing the current character from the string in the variable

           ch = str.charAt(i);

           if(ch == '('||ch=='{'||ch=='[')

               //if the character is starting of the brackets push it into stack

               stack.push(ch);

           else if(ch == ')')

               //if it is closing bracket and the stack is empty then the string is not well formatted

               if(stack.empty())

                   return false;

               else if(stack.peek() == '(')

                   stack.pop();

               else

                   return false;

           else if(ch == '}')

               if(stack.empty())

                   return false;

               else if(stack.peek() == '{')

                   stack.pop();

               else

                   return false;

       }

       //returning the stack content, if the string will be well formed the stack would be empty

       //after all the operations

       return stack.empty();

   }

   //main method

   public static void main(String[] args) {

       //calling function to find if the string is welll formatted or not

       System.out.println(isWellFormed("{}"));

       //calling function to find if the string is welll formatted or not

       System.out.println(isWellFormed("([)]"));

   }

}

5 0
4 years ago
In python:
egoroff_w [7]

Python can be used to implement central of tendencies such as mean, median and mode using the statistic module

The program in Python, where comments are used to explain each line is as follows:

#This imports the statistics module

import statistics

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def calcMode(myList):

   #This prints the mode

   print(statistics.multimode(myList))

#This defines the function that calculates the median

def calcMedian(myList):

   #This prints the median

   print(statistics.median(myList))

#The main method begins here

#This initializes the list

myList = []

#The following iteration gets input for the list

for i in range(10):

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#This calls the calcMode method

calcMode(myList)

#This calls the calcMedian method

calcMedian(myList)

Read more about similar programs at:

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natima [27]

If a robot is able to change its own trajectory as per the external conditions, then the robot is considered the intelligent option (A) is correct.

<h3>What is AI?</h3>

Unlike the natural intelligence exhibited by animals, including humans, artificial intelligence is a form of intelligence demonstrated by robots.

The question is incomplete.

The complete question is:

If a robot can alter its own trajectory in response to external conditions, it is considered to be:

A. intelligent

B. mobile

C. open loop

D. non-servo

E. None of the above

Robots are regarded as intelligent if they can alter their own course in response to environmental factors. These kinds of agents fall into the AI agent or Rational Agent group.

Thus, if a robot is able to change its own trajectory as per the external conditions, then the robot is considered the intelligent option (A) is correct.

Learn more about AI here:

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Which of the following STEM discoverers is known as the “Prince of Math?”
Margarita [4]
The German mathematician & physicist ”Carl Friedrich Gauss”

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Died: February 23, 1855, Göttingen, Germany
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3 years ago
What is e-governence?What are the advantage of it.​
kondaur [170]

Answer:

The advantages of e-government include an improved flow of information from citizen to government, government to citizen, and within government itself. Additionally, e-government helps modernize administration procedures, improving economies and promoting transparency in the process.

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5 0
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