Question

Ice on a lake gets thicker as long as the temperature is below freezing. On a certain lake it took 8 days for the ice to reach a thickness of 3 inches. At what rate was the ice growing over these 8 days in inches per day?

Answer 1

The average rate of growth of the ice can be found by dividing the thickness by the number of days of growth

The growth rate of the ice over the 8 days is 0.375 inches/day

Reason:

The known information on the ice are;

The time it took the ice to reach a thickness of 3 inches = 8 days

Required:

The (average) rate that the ice is growing in c=inches per day

Solution:

$Rate \ of \ growth \ of \ ice= \dfrac{Increase \ in \ thickness}{ Time} = \dfrac{\Delta \ Thickness}{\Delta T}$

Therefore;

$Rate \ of \ growth \ of \ ice= \dfrac{3 \ inches}{ 8 \ days} = 0.375 \ inches/day$

The (average) rate of growth of the ice over the 8 days is 0.375 inches per day

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