If I put a different sticker on the 30th, 50th, and 60th pages will any of the first 600 pages have all 3 stickers?
1 answer:
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Answer:
The horizontal asymptote can be described by the line y = 6
The vertical asymptote can be described by the line x = -2
Step-by-step explanation:
* <em>Lets the meaning of vertical and horizontal asymptotes</em>
- <u><em>Vertical asymptotes</em></u> are vertical lines which correspond to the zeroes
of the denominator of a rational function
- <u><em>A horizontal asymptote</em></u> is a y-value on a graph which a function
approaches but does not actually reach
- If the degree of the numerator is less than the degree of the
denominator, then there is a horizontal asymptote at y = 0
- If the degree of the numerator is greater than the degree of the
denominator, then there is no horizontal asymptote
- If the degree of the numerator is equal the degree of the denominator,
then there is a horizontal asymptote at y = leading coefficient of the
numerator ÷ leading coefficient of the denominator
* <em>Lets solve the problem</em>
∵
∵ The numerator is 6x
∵ The denominator is x + 2
∴ The numerator and the denominator have same degree
∵ The leading coefficient of the numerator is 6
∵ The leading coefficient of the denominator is 1
∴ There is a horizontal asymptote at y = 6/1
∴ <em>The horizontal asymptote can be described by the line y = 6</em>
- Put the denominator equal zero to find its zeroes
∵ The denominator is x + 2
∴ x + 2 = 0
- Subtract 2 from both sides
∴ x = -2
∴ <em>The vertical asymptote can be described by the line x = -2</em>
The function is 
.
To find the x-intercepts, we need to factorize the function. A very good idea is to first try the factors of 36:
f(1)=1-11+36-36, not 0
f(2)=8-44+72-36=-36+72-36=0. Here we have our first root (2).
Now we cad divide f(x) by (x-2) which will give us a quadratic expression, which we can factorize easily (if the discriminant is non negative).
We can also try some other factors of 36. Indeed we can check that
f(3)=27-99+108-36=135-135=0,
and
f(6)=216-396+216-36=0.
Thus, f(x)=(x-2)(x-3)(x-6). Note that if we expanded the right hand side expression, the constant term would be the product of the constants 2, 3, 6.
This is the reason why in the first place we looked at the factors of 36 for the possible zeros of f(x).
Thus, the x-intercepts are (2, 0), (3, 0), (6, 0), or 2, 3, 6.
The y-intercept is f(0), which is -36.
Note that f(0)<f(2) because f(0)=-36 and f(2)=0. This means that at the left side, the graph is coming from - infinity. Similarly,
we can check that f(10)=1000-1100+360-36=224> f(6). That is, to the right of our rightmost root, the graph is getting larger.
Thus, the end behaviors are: the graph goes to + infinity as x goes to + infinity,
and it goes to minus infinity as x goes to - infinity.
To find the x-intercepts, we need to factorize the function. A very good idea is to first try the factors of 36:
f(1)=1-11+36-36, not 0
f(2)=8-44+72-36=-36+72-36=0. Here we have our first root (2).
Now we cad divide f(x) by (x-2) which will give us a quadratic expression, which we can factorize easily (if the discriminant is non negative).
We can also try some other factors of 36. Indeed we can check that
f(3)=27-99+108-36=135-135=0,
and
f(6)=216-396+216-36=0.
Thus, f(x)=(x-2)(x-3)(x-6). Note that if we expanded the right hand side expression, the constant term would be the product of the constants 2, 3, 6.
This is the reason why in the first place we looked at the factors of 36 for the possible zeros of f(x).
Thus, the x-intercepts are (2, 0), (3, 0), (6, 0), or 2, 3, 6.
The y-intercept is f(0), which is -36.
Note that f(0)<f(2) because f(0)=-36 and f(2)=0. This means that at the left side, the graph is coming from - infinity. Similarly,
we can check that f(10)=1000-1100+360-36=224> f(6). That is, to the right of our rightmost root, the graph is getting larger.
Thus, the end behaviors are: the graph goes to + infinity as x goes to + infinity,
and it goes to minus infinity as x goes to - infinity.