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2 years ago

14

Simplify. 6m+7n+5m−3nhow to earn points

1 answer:

lorasvet [3.4K]2 years ago

6 0

Answer:

11m + 4n ...............

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What is the distance between (5,8) and (2,4) by using distance formula

Dimas [21]

Answer:

Distance = 5

Step-by-step explanation:

D= sqrt (x1-x2)^2 + (y1-y2)^2

(5-2)^2 + (8-4)^2=3^2 + 4 ^2 = 9 +16 = 25

Sqrt of 25 = 5

Distance = 5

Hope this helps

7 0

2 years ago

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one bag of toy animals weigh12 ounces. what is the total weight, in ounces, of the bags of toy animals in one crate

LUCKY_DIMON [66]

Assuming I understand what you're saying, if there are 2 boxes in a crate and 18 bags in a box, the answer would be 12 * 36 = 432

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3 years ago

West and Company uses the LIFO method to calculate inventory values. Their beginning inventory consisted of 200 units at a cost

nirvana33 [79]

The total inventory is 200 + 300 + 400 + 100 = 1000. If 300 units remained, the we calculate the cost of the 700 sold via LIFO. These 700 units include the 100 units at $12.00, the 400 units at $11.00, and 200 units at $10.00 (out of the 300 purchased). This is a total cost of 100*12 + 400*11 + 200*10 = 1200 + 4400 + 2000 = $7600.

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2 years ago

Write an equation of a line that contains the point (-2,3) with a slope of 0.

Aleksandr [31]

Answer:

y =3

Step-by-step explanation:

Slope of zero means it is a horizontal line

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3 years ago

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

7 0

2 years ago