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cricket20 [7]
3 years ago
14

Simplify. 6m+7n+5m−3nhow to earn points

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
6 0

Answer:

11m + 4n ...............

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-85 - 8x =2x + 115 anyone know how to do this??
garik1379 [7]

Answer: x= -20

Step-by-step explanation:

Add 85 85 to both sides.

-8x=2x+115+85−8x=2x+115+85

Simplify  2x+115+852x+115+85  to  2x+2002x+200.

-8x=2x+200−8x=2x+200

Subtract 2x2x from both sides.

-8x-2x=200−8x−2x=200

Simplify  -8x-2x−8x−2x  to  -10x−10x.

-10x=200−10x=200

Divide both sides by -10−10.

x=-\frac{200}{10}x=−

​10

​

​200

​​

Simplify  \frac{200}{10}

​10

​

​200

​​   to  20 20.

x= - 20

7 0
3 years ago
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-67 = 6x - 1<br><br>Find x please!​
sasho [114]

Answer:

X=-11

Step-by-step explanation:

-67+1=6x

6x=-66

x=-11

5 0
3 years ago
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Two fractions have the same denominator. Which is greater fraction: the fraction with the greater
Ivan
The fraction with the greater numerator
7 0
3 years ago
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The number of people arriving for treatment at an emergency room can be modeled by a Poisson Distribution with a rate parameter
AlekseyPX

Answer:

a) 0.052 = 5.2% probability that exactly three arrivals occur during a particular hour

b) 0.971 = 97.1% probability that at least three people arrive during a particular hour

c) 5.25 people are expected to arrive during a 45-min period

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Poisson Distribution with a rate parameter of seven per hour.

This means that \mu = 7

(a) What is the probability that exactly three arrivals occur during a particular hour?

This is P(X = 3).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 3) = \frac{e^{-7}*7^{3}}{(3)!} = 0.052

0.052 = 5.2% probability that exactly three arrivals occur during a particular hour.

(b) What is the probability that at least three people arrive during a particular hour? (Round your answer to three decimal places.)

Either less than three people arrive, or at least three does. The sum of the probabilities of these events is 1. So

P(X < 3) + P(X \geq 3) = 1

We want P(X \geq 3), which is

P(X \geq 3) = 1 - P(X < 3)

In which

P(X \geq 3) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-7}*7^{0}}{(0)!} = 0.001

P(X = 1) = \frac{e^{-7}*7^{1}}{(1)!} = 0.006

P(X = 2) = \frac{e^{-7}*7^{2}}{(2)!} = 0.022

So

P(X \geq 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.001 + 0.006 + 0.022 + 0.029

P(X \geq 3) = 1 - P(X < 3) = 1 - 0.029 = 0.971

0.971 = 97.1% probability that at least three people arrive during a particular hour

(c) How many people do you expect to arrive during a 45-min period?

During an hour(60 minutes), 7 people are expected to arrive. So, using proportions:

\frac{45*7}{60} = \frac{3*7}{4} = \frac{21}{4} = 5.25

5.25 people are expected to arrive during a 45-min period

5 0
3 years ago
How will the graph of g(x) = 8x-1 differ from the graph of f(x) = 8x ?
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The graph of y =8x goes through the origin (0,0) the graph of Y = 8x-1 is displaced on the negative y -axis and goes through the point (0, -1)
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