Question

Find the following integrals

Answer 1

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$\sf x - \frac{4}{x} + C$

Step-by-step explanation:

$\sf \longmapsto \int \frac{ {x}^{2} + 4 }{ {x}^{2} }dx \\ \\ \\ \sf \longmapsto \int \frac{ {x}^{2} }{ {x}^{2} } dx + \int \frac{4}{ {x}^{2} } dx \\ \\ \\ \sf \longmapsto \int 1dx + 4 \int \frac{1}{ {x}^{2} } dx \\ \\ \\ \sf \longmapsto x + 4( \frac{{x}^{ -2 + 1}}{ -2 + 1} ) + C \\ \\ \\ \boxed{ \longmapsto x - \frac{4}{x} + C}$

Answer 2

Answer:

x - 4/x

Step-by-step explanation:

Re write as      1 + 4 x^-2

  then you can see the integral is    x -4x^-1