The minimum distance will be along a perpendicular line to the river that passes through the point (7,5)
4x+3y=12
3y=-4x+12
y=-4x/3+12/3
So a line perpendicular to the bank will be:
y=3x/4+b, and we need it to pass through (7,5) so
5=3(7)/4+b
5=21/4+b
20/4-21/4=b
-1/4=b so the perpendicular line is:
y=3x/4-1/4
So now we want to know the point where this perpendicular line meets with the river bank. When it does y=y so we can say:
(3x-1)/4=(-4x+12)/3 cross multiply
3(3x-1)=4(-4x+12)
9x-3=-16x+48
25x=51
x=51/25
x=2.04
y=(3x-1)/4
y=(3*2.04-1)/4
y=1.28
So now that we know the point on the river that is closest to Avery we can calculate his distance from that point...
d^2=(x2-x1)^2+(y2-y1)^2
d^2=(7-2.04)^2+(5-1.28)^2
d^2=38.44
d=√38.44
d=6.2 units
Since he can run at 10 uph...
t=d/v
t=6.2/10
t=0.62 hours (37 min 12 sec)
So it will take him 0.62 hours or 37 minutes and 12 seconds for him to reach the river.
The correct answer would be c. hope this helps
5ml=1 teaspoon
2.5ml=1/2 teaspoon
so 2.5ml is equal to half teaspoon
The value of x is 15.
Solution:
Given ΔPQR 
ΔUTV.
<em>If two triangles are similar, then the corresponding parts are congruent.</em>
Do cross multiplication, we get
⇒ 14(x - 3) = 8(x + 6)
⇒ 14x - 42 = 8x + 48
Add 42 on both sides.
⇒ 14x = 8x + 90
Subtract 8x on both sides.
⇒ 6x = 90
Divide by 6 on both sides.
⇒ x = 15
The value of x is 15.
