I'm guessing the series is supposed to be

By the ratio test, the series converges if the following limit is less than 1.

The first

terms in the numerator's denominator cancel with the denominator's denominator:


also cancels out and the remaining factor of

can be pulled out of the limit (as it doesn't depend on

).

which means the series converges everywhere (independently of

), and so the radius of convergence is infinite.
For this case we have that by definition, the quadratic formula is:
A quadratic equation is of the form:

Option A: This equation can be solved without the quadratic formula

Option B:
This equation is not as easy to solve by factoring or as option A. We can use the quadratic formula.
Option C:

Similarly, this equation can be solved with the quadratic formula
Option D:

In this factored equation we can see that the roots are

Answer:
Option B, C
Answer:
7, 9, 11
Step-by-step explanation:
x+x+2+x+4=5(x+2)-18
3x+6=5x+10-18
3x+6=5x+-8
3x=5x+-14
-2x=-14
x=7
So on the top, you split it up using the difference of squares rule.
You get (x - 6)(x + 6) on the top.
On the bottom, you can undistribute (pull out) -7x.
This gives you -7x(x-6) on the bottom.
Now you can cancel like terms in the numerator and denominator.
You can cancel the (x-6).
You can also move the negative sign from the 7x to the (x + 6)
This leaves you with -(x + 6) over 7x, or (6 - x) over 7x.
To find excluded values, all you need to know is that you can't divide by zero under any circumstances, and you can't have a zero on the top in a rational expression.
The only values for x that would make either of these statements true are if x = 0 (7 × 0 = 0 on the bottom), or if x = 6 (6 - 6 +0 on the top)
So the answer is (6 - x) over 7x, x ≠ 0, 6