The Area is the width<span> times the </span>height<span>: A = w x h;
Then, 64 = w x h;
h = 4 + w;
64 = 4w + w^2;
w^2 + 4w - 64 = 0;
We solve this equation: w1 </span>≈ 6,24 > 0 (okay); w2 ≈ - 10,24 < 0 (not okay);
<span>Finally, h1 </span>≈ 10,24;<span>
</span>
Answer:
Don't let people bring you down you got this
Step-by-step explanation:
Answer:
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Step-by-step explanation:
parallel lines have the same slope
The slope-intercept form of a linear equatio is y=mx+b, where m stands for the "slope of the line" and b stands for the "y-intercept of the line"
They give you the equation y= -5/6x+3 Notice this is already on the slope-intercept form, so in this case the slope is -5/6 and the y-intercept is 3
You want an equation of the line that is parallel to the given line. The slopes must be the same, so m=-5/6
So far we have y=-5/6x + b
We don't have b yet but that can be found using the given point (6,-1) which tells you that "x is 6 when y is -1"
Replace that on the equation y=-5/6x + b and you get
-1 = (-5/6)(6) + b
-1 = -5 +b
4 = b
b = 4
We found b, or the y-intercept
Go back to the equation y = -5/6 x + b and replace this b with the b we just found
y = -5/6x + 4
Answer:
The two roots of the quadratic equation are
Step-by-step explanation:
Original quadratic equation is 
Divide both sides by 9:
Add 
to both sides to get rid of the constant on the LHS
==> 
Add 
to both sides
This simplifies to
Noting that (a + b)² = a² + 2ab + b²
If we set a = x and b = 
we can see that
= 
So
Taking square roots on both sides
So the two roots or solutions of the equation are
and 
So the two roots are
and
