Find radius of the circle whose center is (5,-2) and the circle passes through (0,-6)
1 answer:
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Answer:
y=1/2x+2
Step-by-step explanation:
The equations come in the form of y=mx+c, where m is the gradient and c is the y-intercept. Looking at the graph we know that the y-intercept is (0,2), so that rules out options B and C.
To find the gradient is a little more tricky, but we can follow the formula:
, where rise is the vertical value and run is the horizontal value
So we sub in our values:
And simplify:
So now we sub in our new found values into y=mx+c:
y=1/2x+2
