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2 years ago

Find radius of the circle whose center is (5,-2) and the circle passes through (0,-6)

1 answer:

8 0

I think its The equation of a circle with its center at the origin is x2 + y2 = r2. Replacing the x and y in this equation with –5 and 12, respectively, you get (–5)2 + (12)2 = 25 + 144 = 169 = r2. The square root of 169 is 13, so the radius is 13.

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division equation where 13 is quotient with the dividend a whole number and a unit fraction is the divisor

lys-0071 [83]

The division equation that has a quotient of 13 is 1/1/13 = 13

<h3>How to determine the equation?</h3>

The given parameters are:

Quotient = 13
Dividend = Whole number
Divisor = Unit fraction i.e. 1/n where n is an integer.

A division equation is represented as:

Dividend/Divisor = Quotient

Substitute 13 for the Quotient

Dividend/Divisor = 13

Recall that:

Unit fraction = 1/n

So, we have:

Dividend/1/n = 13

Let n = 13.

So, we have:

Dividend/1/13 = 13

This gives

13 * Dividend = 13

Divide both sides by 13

Dividend = 1

So, we have:

1/1/13 = 13

Hence, the division equation is 1/1/13 = 13

Read more about division equations at:

brainly.com/question/1622425

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3 0

1 year ago

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garri49 [273]

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2 years ago

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kykrilka [37]

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