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SOVA2 [1]
3 years ago
6

Find radius of the circle whose center is (5,-2) and the circle passes through (0,-6)

Mathematics
1 answer:
olga2289 [7]3 years ago
8 0

I think its The equation of a circle with its center at the origin is x2 + y2 = r2. Replacing the x and y in this equation with –5 and 12, respectively, you get (–5)2 + (12)2 = 25 + 144 = 169 = r2. The square root of 169 is 13, so the radius is 13.

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Answer

given,

work = 5 J

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W = \dfrac{1}{2}kx^2

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     x = 0.0205 m

     x = 2.05 cm

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