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Oksanka [162]
3 years ago
14

Write the slope intercept form equation of the line given in graph

Mathematics
1 answer:
notka56 [123]3 years ago
4 0

Answer:

y = 2/5x -2

Step-by-step explanation:

First, establish two points. I'll use the intercepts for this problem.

(5, 0), (0, -2)

To find slope, divide change in y by change in x.

Change in y --> 0 - (-2) = 2

Change in x --> 5 - 0 = 5

<em>Slope = 2/5</em>

<u>Next, find intercept.</u>

Plug in slope for one of the points and find how you can make that equal to the y coordinate by adding/subtracting

0 · 2/5 + ? = -2

? = -2

<em>y intercept = -2</em>

Or if the line intercepts the y-axis at a definite point like this graph, just find where it intercepts.

<u>Putting it Together</u>

Now just put this into slope-intercept form which is y = mx + b, where m is the slope and b is the y-intercept.

<em>y = 2/5x - 2</em>

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Answer:

x=3

Step-by-step explanation:

When you substitute x = 3 to both equations, you get y = -4 for both so that is a solution

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Answer:

$954.78

Step-by-step explanation:

Since it increases by 8.5%, all you have to do is multiply 879.98 by 1.085.

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Given the coordinates A (5, 7, -2) and B (8, 3, 4) in 3d space, express AB as:
lys-0071 [83]
The vector AB is found by subtracting the coordinates of point B from the coordinates of point A => (8, 3, 4) - (5, 7, - 2)

(8, 3, 4) - (5, 7, - 2) = (3, - 4, 6)

=>

a) a 3 x 1 column =

|  3  |
| -4  |
|  6  |

b) xi + yj + zk

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4 years ago
What are the endpoint coordinates for the midsegment of △PQR that is parallel to PQ¯¯¯¯¯?
andriy [413]

Answer:

M(x₄ ,y₄) = (-3.5 , 0.5)  and

N (x₅ ,y₅) = ( -1 , -0.5 )

Step-by-step explanation:

Let the endpoint coordinates for the mid segment of △PQR that is parallel to PQ be

M(x₄ ,y₄) and N(x₅ ,y₅) such that MN || PQ

point P( x₁ , y₁) ≡ ( -3 ,3 )

point Q( x₂ , y₂) ≡ (2 , 1 )

point R( x₂ , y₂) ≡ (-4 , -2)  

To Find:

M(x₄ ,y₄) = ?  and

N (x₅ ,y₅) = ?

Solution:

We have Mid Point Formula as

Mid\ point(x,y)=(\frac{x_{1}+x_{2} }{2}, \frac{y_{1}+y_{2} }{2})

As M is the mid point of PR and N is the mid point of RQ so we will have

Mid\ pointM(x_{4} ,y_{4})=(\frac{x_{1}+x_{3} }{2}, \frac{y_{1}+y_{3} }{2})

Mid\ pointN(x_{5} ,y_{5})=(\frac{x_{2}+x_{3} }{2}, \frac{y_{2}+y_{3} }{2})

Substituting the given value in above equation we get

Mid\ pointM(x_{4} ,y_{4})=(\frac{-3+-4 }{2}, \frac{3+-2} }{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(\frac{-7} }{2}, \frac{1}{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(-3.5, 0.5)

Similarly,

Mid\ pointN(x_{5} ,y_{5})=(\frac{2+-4 }{2}, \frac{1+-2 }{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(\frac{-2 }{2}, \frac{-1}{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(-1, -0.5)

∴ M(x₄ ,y₄) = (-3.5 , 0.5)  and

  N (x₅ ,y₅) = ( -1 , -0.5 )

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3 years ago
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Klio2033 [76]
Check the picture below

if that red segment, GJ, is parallel to the AE base segment of the triangle, then, the segment GJ is the midsegment of the triangle, and by the side-splitter theorem, those two triangles are similar.

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