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REY [17]
3 years ago
15

A six-sided number cube is labeled with the numbers 1-6, one number on each face. Each number is used exactly once.

Mathematics
1 answer:
I am Lyosha [343]3 years ago
8 0

Answer:

36

Step-by-step explanation:

This question can be solved using fundamental counting principle which means to say that if there are "m" ways  of doing one thing and there are "n" ways of doing other thing then there are total "m*n" ways of doing other things.

For example: if there are 4 type of pens and 3 type of notebook then there are "4*3" ways to write on notebook using  the pens.

_____________________________________________________

Using the above mentioned principle we have

 six sided cube with number 1 to 6  written on it hence in first roll there are six possible outcome(1 or 2 or 3 or 4 or 5 or 6) similarly there are 6 possible outcome in other roll as well.

If the combination of outcome is to be deduced then there are 6*6 ways of outcome based on  fundamental counting principle.

Hence there are 6*6 = 36 ways of possible outcomes.

_________________________________________________________

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Answer:

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p_v =P(z>1.9)=0.0287  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=12.95 represent the sample mean

\sigma=3 represent the population standard deviation for the sample  

n=36 sample size  

\mu_o =12 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 12, the system of hypothesis would be:  

Null hypothesis:\mu \leq 12  

Alternative hypothesis:\mu > 12  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

P-value  

Since is a right tailed test the p value would be:  

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Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

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