Answer:You would need 9 buses for everyone
Step-by-step explanation:with 8 buses you would have taken 200 students so you'd need one more bus for the other five.
I think that the answer is b but I am not sure
25X4=100
4X_=88
88÷4=22
So she got 22 problems correct.
~JZ
Hope you understand
<span>A certain airplane has two independent alternators to provide electrical power. the probability that a given alternator will fail on a one-hour flight is 0.019.
This is a binomial probability situation, since it's "pass or fail." The prob. of failure is 0.019. Since the alternators are separate and independent, the prob. that two will fail is the product of 0.019 and 0.019, or 3.61 to the power -4 of 10. The latter can also be written as 0.000361.
The probability that one alternator will fail is 1-0.019, or 0.981.
The probability that neither alternator will fail is (0.981)^2=0.9624 (to four decimal place accuracy).
</span><span>What is the probability that at least one fails? This probability is equal to the complement of the probability that ONE will fail, which on the TI 84 Plus can be calculated as 1-binompdf(2,0.981,0), which comes out to 0.000361. </span>
