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Sergeu [11.5K]
3 years ago
15

Ind the surface area of the square pyramid shown below.

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
3 0

Answer:

do u times it??

Step-by-step explanation:

or add? because I don't know

Dmitry [639]3 years ago
3 0

Answer:

the answer is 44.84

{4 }^{2}  + 2(4) \sqrt{ \frac{ {4}^{2} }{4} }  +  {3}^{2}

{a}^{2}  + 2a \sqrt{ \frac{ {a}^{2} }{4} }  +  {h}^{2}

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8. A cable car travels 2236 m to climb a mountain that is 1000 m high. It then travels 1414 m to descend 1000 m on the other sid
frutty [35]

Answer:

3000 m

Step-by-step explanation:

Using Pythagoras theorem

2236^2=1000^2+|AB|^2\\|AB|^2=2236^2-1000^2\\|AB|^2=3999696\\|AB|=\sqrt{3999696} \\=1999.9

Similarly

1414^2=1000^2+|BC|^2\\|BC|^2=1414^2-1000^2\\|BC|^2=999696\\|BC|=\sqrt{999696} \\=999.7m

Length of the Tunnel = |AB|+|BC|

=1999.9+999.7

=2999.6

=3000 m

4 0
3 years ago
A swimming pool whose volume is 10 comma 000 gal contains water that is 0.03​% chlorine. Starting at tequals​0, city water conta
Katarina [22]

Answer:

C(60) = 2.7*10⁻⁴

t = 1870.72 s

Step-by-step explanation:

Let x(t) be the amount of chlorine in the pool at time t. Then the concentration of chlorine is  

C(t) = 3*10⁻⁴*x(t).

The input rate is 6*(0.001/100) = 6*10⁻⁵.

The output rate is 6*C(t) = 6*(3*10⁻⁴*x(t)) = 18*10⁻⁴*x(t)

The initial condition is x(0) = C(0)*10⁴/3 = (0.03/100)*10⁴/3 = 1.

The problem is to find C(60) in percents and to find t such that 3*10⁻⁴*x(t) = 0.002/100.  

Remember, 1 h = 60 minutes. The initial value problem is  

dx/dt= 6*10⁻⁵ - 18*10⁻⁴x =  - 6* 10⁻⁴*(3x - 10⁻¹)               x(0) = 1.

The equation is separable. It can be rewritten as dx/(3x - 10⁻¹) = -6*10⁻⁴dt.

The integration of both sides gives us  

Ln |3x - 0.1| / 3 = -6*10⁻⁴*t + C    or    |3x - 0.1| = e∧(3C)*e∧(-18*10⁻⁴t).  

Therefore, 3x - 0.1 = C₁*e∧(-18*10⁻⁴t).

Plug in the initial condition t = 0, x = 1 to obtain C₁ = 2.9.

Thus the solution to the IVP is

x(t) = (1/3)(2.9*e∧(-18*10⁻⁴t)+0.1)

then  

C(t) = 3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴t)+0.1)

If  t = 60

We have

C(60) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴*60)+0.1) = 2.7*10⁻⁴

Now, we obtain t such that 3*10⁻⁴*x(t) = 2*10⁻⁵

3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 2*10⁻⁵

t = 1870.72 s

7 0
3 years ago
1) Use the point at (4, 6) to answer the following. *
galben [10]
B. Mark bought 4 packs of gum for $1.5 each. 6 dollars in total. The 4 packs of gum is on the x axis (x, y) and the the total is 6 dollars.
4 0
3 years ago
What is the arc length S what is shown below?
Solnce55 [7]

Answer:

  14 cm

Step-by-step explanation:

The applicable formula is ...

  s = rθ

  s = (7 cm)(2) = 14 cm

3 0
3 years ago
What values are excluded from the domain and range of the function f(x)=x+3/2x+5?
Alexxandr [17]

Please see attached image with my answer.


3 0
3 years ago
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