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Bumek [7]
3 years ago
12

Rewrite using the power of the product property.81x^4y^8​

Mathematics
1 answer:
amm18123 years ago
4 0

81 is 3^4, so

3^4 \cdot x^4 \cdot \left(y^2\right)^4 = \left(3 \cdot x \cdot y^2\right)^4 = \boxed{\left(3xy^2\right)^4}

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PLEASE HELP ME !!!!!!!!!!!!!!!!!!!!!
dsp73

Answer:

the required answer is 64

Step-by-step explanation:

b/4 =16

b = 16 × 4

= 64

7 0
3 years ago
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I need help I would really thank whoever answers this for me
Mars2501 [29]
To do these problems, you plug in the ‘n’ value given into the equation.

a. 6j - 3 : j = 4
6(4) - 3
24 - 3
21

b. 1/2b + 5 : b = 14
1/2(14) + 5
7 + 5
12

c. 8 + 4k : k = 3.5
8 + 4(3.5)
8 + 14
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6 0
3 years ago
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I know the answer is no solution but I don't know how to get it☹️ plz help!
Crank
When a linear equation is in the form y = mx + c, the c, or constant, is the intercept on the y axis, meaning it crosses the y axis at (0, 1).

The gradient (1/3 in this case) is how much the y increments (or decrements) per increase of 1 of the value of x.

This would mean that there would be one point at (0, 1), and another at (3, 2). Draw a line from these two points and beyond, and that is the graph sketched.
3 0
4 years ago
What is the period of y=3cot(4x−3π)
Stells [14]
Hello!

hint: we can rewrite your function as below:

<span>3/<span>tan<span>(<span>4x−3π</span>) = </span></span></span>3(1+tan4xtan3π)/tan4x−tan3π = 

=<span>3/<span>tan<span>(<span>4x</span>) = </span></span></span>3cot<span>(<span>4x</span><span>)

</span></span>now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:

<span>"4P=π"


Hope this Helps! Have A Wonderful Day! :)</span>
4 0
3 years ago
Find the value of x. (5x+15) (6x-10)
Blizzard [7]
(5x+15)(6x-10)
= 30x^2 + 30x - 50x - 150
= 30x^2 - 20x - 150
4 0
4 years ago
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