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2 years ago

Rewrite using the power of the product property.81x^4y^8

Mathematics

1 answer:

amm18122 years ago

4 0

81 is 3^4, so

$3^4 \cdot x^4 \cdot \left(y^2\right)^4 = \left(3 \cdot x \cdot y^2\right)^4 = \boxed{\left(3xy^2\right)^4}$

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If a diameter is 12.5 cm, what is the radius?

Jlenok [28]

Answer:

6.25

Step-by-step explanation:

8 0

2 years ago

please solve all of them Elaine bought a total of 15 shirts and pairs of pants She bought 7 more shirts then pants how many of e

mihalych1998 [28]

Answer

Question 1

4 pants

11 shirts

Question 2

Shady has 30 video games.

Preston has 19 video games.

Question 3

1 muffin costs $1.5

1 quart of milk costs $3

Explanation

Question 1

Let the number of shirts be s

Let the number of pants be p

She bought a total of 15 shirts and shirts

s + p = 15

She bought 7 more shirts than pants.

s = 7 + p

So, we can solve the simultaneous equation.

s + p = 15

s = 7 + p

Substitute for s in equation 1

s + p = 15

7 + p + p = 15

7 + 2p = 15

2p = 15 - 7

2p = 8

Divide both sides by 2

(2p/2) = (8/2)

p = 4 pants

s = 7 + p = 7 + 4 = 11 shirts

Question 2

Let the number of games Shady has be s

Let the number of games Preston has be p

Together, they have a total of 49 video games

s + p = 49

Shady has 11 more games than Preston.

s = 11 + p

So, we can solve the simultaneous equation.

s + p = 49

s = 11 + p

Substitute for s in equation 1

s + p = 49

11 + p + p = 49

11 + 2p = 49

2p = 49 - 11

2p = 38

Divide both sides by 2

(2p/2) = (38/2)

p = 19 video games

s = 11 + p = 11 + 19 = 30 video games

Question 3

Let the cost of a muffin be m

Let the cost of a quart of milk be q

The cost of 8 muffins and 2 quarts of milk is $18.

8m + 2q = 18

The cost of 3 muffins and 1 quart of milk is $7.50

3m + q = 7.5

So, we can solve the simultaneous equation

8m + 2q = 18

3m + q = 7.5

Solving this,

m = 1.5 dollars

q = 3 dollars

Hope this Helps!!!

3 0

1 year ago

Three Texas drovers met on a highway and began to dicker as follows:

Alik [6]

Answer:

Jim's: 7
Duke's: 21
Hank's: 11

Step-by-step explanation:

Let J, D, and H represent the drove sizes of Jim, Duke, and Hank.

2(H -6 + 1) = (J +6 -1) . . . . . Hank's offer

3(D -14 +1) = (H +14 -1) . . . . Duke's offer

6(J -4 +1) = (D +4 -1) . . . . . . Jim's offer

These equations can be simplified to ...

2H - J = 15

3D - H = 52

6J - D = 21

<u>Solution</u>

Adding twice the second equation to the first gives ...

2(3D -H) +(2H -J) = 2(52) +(15)

6D -J = 119

Adding 6 times the third equation to this one gives ...

6(6J -D) +(6D -J) = 6(21) +(119)

35J = 245

J = 7

Using this value in the third equation gives ...

6(7) -D = 21

42 -21 = D = 21

Using the value of J in the first equation gives ...

2H -7 = 15

H = (15 +7)/2 = 11

Then the solution is (J, D, H) = (7, 21, 11).

Jim's drove had 7 animals; Duke's drove had 21 animals; Hank's drove had 11 animals.

5 0

2 years ago

HELPPP

GalinKa [24]

Answer:

HL (Hypotenuse Leg)

Step-by-step explanation:

You have BC=CD (Because of reflexive property), AC=DC, and measure of BAC is equal to the measure of BDC, which is 90 degrees. Since these triangles are right and they have a hypotenuse and a leg congruent, you can say that they are congruent because of HL.

4 0

2 years ago

To show that polygon ABCDE is congruent to polygon FGHIJ, a must be used to make the two polygons coincide. A sequence of two tr

Sati [7]

Hello.

The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 2 (translation and rotation).

A rotation translation must be used to make the two polygons coincide.

A sequence of transformations of polygon ABCDE such that ABCDE does not coincide with polygon FGHIJ is a translation 2 units down and a 90° counterclockwise rotation about point D

Have a nice day

7 0

3 years ago

Read 2 more answers

Rewrite using the power of the product property.81x^4y^8​

Rewrite using the power of the product property.81x^4y^8