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Sergeeva-Olga [200]
2 years ago
13

If six pounds of grape juice is $3, how much would it cost to buy 3,4, and 5 pounds of grape juice?​

Mathematics
2 answers:
Svetllana [295]2 years ago
7 0

Answer:

It would cost $9 for 3 pounds, $12 for 4, and $15 for 5.

Step-by-step explanation:

I hope I understood what you we're asking correctly, sorry if not. :)

Andrej [43]2 years ago
6 0

Answer:

5=2.50$

4= 2.00$

3= 1.50

2= 1.00$

1= .50cents

Step-by-step explanation:

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1.44 divided by 16 which is 0.09 and to check answer you take 0.09 and multiply by 15 and you get 1.44
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3 years ago
Please help urgently.
const2013 [10]

Answer:

No

Step-by-step explanation:

He's only won 50% of the games bc he lost one and one one. 1/2

7 0
2 years ago
Can you help me with both don’t know if second one is right
erma4kov [3.2K]

Answer:

1. $67.72

2. It's correct.

Step-by-step explanation:

1.

bill: $68.89

discount: $10

tip: 15%

Calculate the total with the discount.

68.89-10=58.89

Now calculate 15% of that.

Convert 15% to decimal by dividing by 100

\frac{15}{100}=0.15

Multiply

0.15(58.89)=8.83

Add this to the original amount.

58.89+8.83=67.72

----------------------------------------------------------------------------

Calculate 20% of 148.25

Convert 20% to decimals by dividing by 100

\frac{20}{100}=0.20

Multiply

0.20(148.25)=29.65 This is how much they will tip.

Add this to the original bill;

148.25+29.65=177.90

7 0
3 years ago
I need help with my math homework. <br> Find the slope of each line.<br> Thanks!
guajiro [1.7K]
7 is infinite 6 is 4/3 5 is zero 4 is negative 5/4
6 0
2 years ago
<img src="https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BE%7D%7B%20%5Csqrt%7BR%20%7B%7D%5E%7B2%7D%20%2B%20W%20%7B%7D%5E%7B2%7D%20L%
AleksandrR [38]

Answer:

R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Step-by-step explanation:

Squaring both sides of equation:

     I^2 = (ER)^2/(R^2 + (WL)^2)

<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)

<=>(ER)^2 - (IR)^2 = (IWL)^2

<=> R^2(E^2 - I^2) = (IWL)^2

<=> R^2 = (IWL)^2/(E^2 - I^2)

<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Hope this helps!

7 0
3 years ago
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