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Sergeeva-Olga [200]
2 years ago
13

If six pounds of grape juice is $3, how much would it cost to buy 3,4, and 5 pounds of grape juice?​

Mathematics
2 answers:
Svetllana [295]2 years ago
7 0

Answer:

It would cost $9 for 3 pounds, $12 for 4, and $15 for 5.

Step-by-step explanation:

I hope I understood what you we're asking correctly, sorry if not. :)

Andrej [43]2 years ago
6 0

Answer:

5=2.50$

4= 2.00$

3= 1.50

2= 1.00$

1= .50cents

Step-by-step explanation:

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Determine whether the given value is a solution of the equation.
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Answer:

84 is a solution.

Step-by-step explanation:

To find out if 84 is a solution or not, we plug in the value and simplify.

  • (84)/14 = 6
  • 6 = 6

Therefore, 84 is a solution.

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2 years ago
A clothing company sells slacks that are either blue or gray and pleated or non-pleated. Last month, the company sold 5 times as
abruzzese [7]

Answer:

88

Step-by-step explanation:

5GP= BP

2BNP= GNP

BP+BNP=333

GP+GNP=225

BNP= 333-BP

BNP= 333-5GP

GP= 225-GNP

GP= 225-2BNP

BNP=333-5(225-2BNP)

BNP=333-1125+10BNP

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Hope it helps :)

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3 years ago
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A line crosses the x-axis at -7 and the y axis at 10. Is the slope of the line positive or negative?
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The line is positive

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It wouldve been negative if it slanted to the left.

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2 years ago
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140cm<br> 3 cm<br> 12 cm<br> 8 cm<br> Find surface area?
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3 years ago
Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different
N76 [4]

Answer:

(a)  As time increases, the amount of water in the pool increases.

     11 gallons per minute

(b)  65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

We are told that Ann adds water at a constant rate.  Therefore, this can be modeled as a linear function.  

The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

Choose 2 ordered pairs from the table:

\textsf{let}\:(x_1,y_1)=(8, 153)

\textsf{let}\:(x_2,y_2)=(12,197)

Input these into the slope formula:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11

Therefore, the rate at which the water in the pool is increasing is:

<u>11 gallons per minute</u>

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

y-y_1=m(x-x_1)

\implies y-153=11(x-8)

\implies y-153=11x-88

\implies y=11x-88+153

\implies y=11x+65

When Ann had added no water, x = 0.  Therefore,

y=11(0)+65

y=65

So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.

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