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melamori03 [73]
3 years ago
9

What is the GCF for 70 and 90 

Mathematics
2 answers:
Anna [14]3 years ago
7 0
The GCF for 70 and 90 is 10.
mrs_skeptik [129]3 years ago
4 0
Pretty sure the GCF of 70 and 90 is 10
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The three linear equations have y intercept of -3.8 and 7 respectively. Yet, a function can have only one y intercept. which of
k0ka [10]

Answer:

agagasg

Step-by-step explanation:

5 0
3 years ago
(5 + 4 - 2) x (-2)=? A.-14 B.14 C.-22 D.22
Sveta_85 [38]
(5 + 4 - 2) x (-2)
= (9 - 2) x (-2)
= (7) x (-2)
= - 14 (Answer A)
7 0
4 years ago
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What two numbers multiply to 16 and add to 4?
alukav5142 [94]

You said that (xy) = 16, and (x+y) = 4 .

From the second equation you can get [ x = 4 - y ],
then substitude that for 'x' in the first equation, and
finally, rearrange the first equation to read
                                                                   <u>x² - 4x + 16 = 0</u>

Don't even try to factor that quadratic equation.  Go straight
to the quadratic formula, and the two solutions you find are ...

         <em>x = 2 + i 2√3</em>
and
         <em>x = 2 - i 2√3</em> .

Those are the two number that do what you want.

There are no <u>real</u> numbers that can do it.


7 0
3 years ago
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Suppose that prices of a certain model of new homes are normally distributed with a mean of $150,000. use the 68-95-99.7 rule to
Novosadov [1.4K]

Answer:

We want to find the percentage of values between 147700 and 152300

P(147700

And one way to solve this is use a formula called z score in order to find the number of deviations from the mean for the limits given:

z= \frac{x-\mu}{\sigma}

And replacing we got:

z=\frac{147700-150000}{2300}=-1

z=\frac{152300-150000}{2300}=1

So then we are within 1 deviation from the mean so then we can conclude that the percentage of values between $147,700 and $152,300 is 68%

Step-by-step explanation:

We define the random variable representing the prices of a certain model as X and the distirbution for this random variable is given by:

X \sim N(\mu = 150000, \sigma =2300

The empirical rule states that within one deviation from the mean we have 68% of the data, within 2 deviations from the mean we have 95% and within 3 deviations 99.7 % of the data.

We want to find the percentage of values between 147700 and 152300

P(147700

And one way to solve this is use a formula called z score in order to find the number of deviations from the mean for the limits given:

z= \frac{x-\mu}{\sigma}

And replacing we got:

z=\frac{147700-150000}{2300}=-1

z=\frac{152300-150000}{2300}=1

So then we are within 1 deviation from the mean so then we can conclude that the percentage of values between $147,700 and $152,300 is 68%

7 0
4 years ago
A cylinder has a height that is 2 times as large as its radius. The lateral area of the cylinder is 16π square units. What is th
Juliette [100K]
The length of the radius of the cylinder is 2 units.

The lateral surface area of a cylinder = <span>2πrh</span>
where, r = base radius
            h = height of cylinder
Now, height of cylinder = 2r units
          
⇒ 16 π =  2×π×r×<span>h
</span>⇒ 16 π =  2×π×r×2r
⇒  r^{2} = 4
⇒ r = 2 units
Thus, radius is 2 units.

8 0
3 years ago
Read 2 more answers
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