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2 years ago

A student can type 65 words in 2 minutes. How many words can student tupe in 20 minutes?

2 answers:

6 0

650 Because if the student can do 65 words in 2 mins, you would have to do 20 divided by 2 and get 10 then times 10 by 65 which is 650 in 20 mins.

Natasha_Volkova [10]2 years ago

5 0

If you know that a student can type 65 words in2 minutes, then they can type 650 in 20 minutes. You can figure this out because 2 x 10=20. Multiply 65 by 10 to see how many words the student could type in 29 minutes.

The answer is 650 words!

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Examine the following sequence 1, 4, 9, 16, 25…. Why is 36 the next number in the sequence? Because the pattern is

Marrrta [24]

Because the pattern is a Geometric sequence.

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3 years ago

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six times jason collection of books and one third of nathan collection add up to 134 books. one third of jason collection and na

raketka [301]

Answer:

j = 21 and n = 14

Step-by-step explanation:

we have the equations:

6j + n/3 = 134

j/3 + n = 31

54j + 3n = 1206

j + 3n = 93

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3 years ago

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Step-by-step explanation:

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3 years ago

. If α and β are the roots of

Lostsunrise [7]

Answer:

$18x^2+85x+18 = 0$

Step-by-step explanation:

Given Equation is

=> $2x^2+7x-9=0$

Comparing it with $ax^2+bx+c = 0$ , we get

=> a = 2, b = 7 and c = -9

So,

Sum of roots = α+β = $-\frac{b}{a}$

α+β = -7/2

Product of roots = αβ = c/a

αβ = -9/2

Now, Finding the equation whose roots are:

α/β ,β/α

Sum of Roots = $\frac{\alpha }{\beta } + \frac{\beta }{\alpha }$

Sum of Roots = $\frac{\alpha^2+\beta^2 }{\alpha \beta }$

Sum of Roots = $\frac{(\alpha+\beta )^2-2\alpha\beta }{\alpha\beta }$

Sum of roots = $(\frac{-7}{2} )^2-2(\frac{-9}{2} ) / \frac{-9}{2}$

Sum of roots = $\frac{49}{4} + 9 /\frac{-9}{2}$

Sum of Roots = $\frac{49+36}{4} / \frac{-9}{2}$

Sum of roots = $\frac{85}{4} * \frac{2}{-9}$

Sum of roots = S = $-\frac{85}{18}$

Product of Roots = $\frac{\alpha }{\beta } \frac{\beta }{\alpha }$

Product of Roots = P = 1

The Quadratic Equation is:

=> $x^2-Sx+P = 0$

=> $x^2 - (-\frac{85}{18} )x+1 = 0$

=> $x^2 + \frac{85}{18}x + 1 = 0$

=> $18x^2+85x+18 = 0$

This is the required quadratic equation.

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2 years ago

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Three billion, four hundred million years old. Write in standard form and expanded form.

Brums [2.3K]

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2 years ago