Answer:
5.37% probability that a bulb picked at random from this company product will have a life time of at least 300 hours
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
What is the probability that a bulb picked at random from this company product will have a life time of at least 300 hours?
This is 1 subtracted by the pvalue of Z when X = 300. So
has a pvalue of 0.9463
1 - 0.9463 = 0.0537
5.37% probability that a bulb picked at random from this company product will have a life time of at least 300 hours
Answer:
See below
Step-by-step explanation:
√160c⁵d⁴
= √160 * √c⁵ * √d⁴
= √16 * √10 * √c² * √c² * √c * √d² * √d²
= 4 * √10 * c * c * √c * d * d
= 4c²d²√10c
Answer:
1. answer is D
2. Answer is D
3.Answer is B
4. Answer is C
5. Answer is B
6. Answer is D
7.Answer is D
Step-by-step explanation:
Complementary angles are equal to 90 degrees. 90 - 75 = 15 degrees
9514 1404 393
Answer:
see attached
Step-by-step explanation:
The formula tells you the diameter is 2 times the radius. Pick some values for radius and multiply them by 2 to get the diameter. The graph will be a straight line through the origin with a slope of 2.
(Strictly speaking, the graph should not extend to negative values, as negative values for radius and diameter make no sense in the real world.)
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We did not put unit labels (cm, feet, yards, km, light-years, etc.) on the graph axes. For a slope of 2, the graph needs the same units on both axes. They can be whatever units of distance you might choose.
