If the length of rectangular school hall is 4 times the width and the perimeter be 55m, then the length is 22m and the width of the school hall be 5.5m.
Given that the length of rectangular school hall is 4 times the width.
We are required to find the length and breadth of the rectangle which has the length be 4 times the width.
Perimeter of rectangle is the sum of all the length and breadth of that rectangles.
Perimeter of rectangle is given as 55m
Perimeter=2(L+B)
let the width of rectangle be x.
Length of that rectangle be 4x.
According to question,
2(x+4x)=55
2*5x=55
10x=55
x=55/10
x=5.5 m
Width be 5.5 m.
Length of rectangle be 4*5.5=22m.
Hence if the length of rectangular school hall is 4 times the width then the length is 22m and the width of the school hall be 5.5m.
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Answer: The answer is -50
because 80 + -50 = 30 and 30 + -30= 0 .
The answer to your question is 2250
Answer:
-1
Step-by-step explanation:
-3x(-5)-16
15-16
-1
Answer:
c
Step-by-step explanation:
Triangle ABD is congruent to triangle ACD so segment BD is Congruent to segment DC
Therefore DC=14
