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Anna [14]
3 years ago
6

Factor the trinomial x^2-2x-35

Mathematics
2 answers:
Oliga [24]3 years ago
3 0

Answer:

(x-7)(x+5)

Step-by-step explanation:

erastova [34]3 years ago
3 0

Answer:

(x + 5)(x - 7)

Step-by-step explanation:

x² - 2x - 35

Now we need to find two numbers whose product will be 35 and sum or difference will be 2. They are 7 and 5.

7 x 5 =35

7 - 5 = 2

So

= x² + 5x - 7x - 35

Taking x common from 1st two terms and -7 from last two.

= x(x + 5) - 7(x + 5)

Taking (x + 5) common

= ( x + 5)(x - 7)

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Hunter-Best [27]

Answer:

a) The table of values represents the ordered pairs formed by the elements of the sequence (a_{i}) (range) and their respective indexes (i) (domain):

i         a_{i}

1         6

2        11

3        16

4        21

5        26

b) The algebraic expression for the general term of the sequence is a(i) = 6 + 5\cdot (i - 1).

c) The 25th term in the sequence is 126.

Step-by-step explanation:

a) Make a table of values for the sequence 6, 11, 16, 21, 26, ...

The table of values represents the ordered pairs formed by the elements of the sequence (a_{i}) (range) and their respective indexes (i) (domain):

i         a_{i}

1         6

2        11

3        16

4        21

5        26

b) Based on the table of values, we notice a constant difference between two consecutive elements of the sequence, a characteristic of arithmetic series, whose form is:

a(i) = a_{1} + r\cdot (i - 1) (1)

Where:

a_{1} - First element of the sequence.

r - Arithmetic difference.

i - Index.

If we know that a_{1} = 6 and r = 5, then the algebraic expression for the general term of the sequence is:

a(i) = 6 + 5\cdot (i - 1)

c) If we know that a(i) = 6 + 5\cdot (i - 1) and i = 25, then the 25th term in the sequence is:

a(25) = 6 + 5\cdot (25 - 1)

a(25) = 126

The 25th term in the sequence is 126.

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