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polet [3.4K]
3 years ago
13

The radius of a cylindrical construction pipe is 2ft . if the pipe is 23ft long, what is its volume? use the value 3.14 for π ,

and round your answer to the nearest whole number. be sure to include the correct unit in your answer.
Mathematics
1 answer:
Pani-rosa [81]3 years ago
5 0
Answer is v=πr^2h =288.88ft
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Find the arc length of ADC. Round to the nearest hundredth.<br> BA = 6.5 cm
MakcuM [25]
2190.5 cm.

360 degrees - 23 degrees = 337 degrees

337 degrees x 6.5 cm = 2190.5 cm
7 0
3 years ago
Green Valley Middle School wants to raise $7,500 for new equipment. If grades 6 and 7 each raise $2,450.25, how much money does
Aleksandr [31]

Answer:

2599.50

Step-by-step explanation:

7500 - 2(2450.25) = 2599.50

6 0
3 years ago
Identify the first operation needed in this equation
ruslelena [56]
Addition is the first step in solving the equation. Here is how to solve this problem:

x/3 - 3 = 11
+ 3 + 3
------------------------
x
(3) -------- = 14(3)
3

x = 42

5 0
3 years ago
A luxury liner leaves a port on a bearing of 110 degrees and travels 8.8 miles. It then turns due west and travels 2.4 miles. Ho
myrzilka [38]

Answer:

Distance= 6.6 miles

Bearing= N 62.854°W

Step-by-step explanation:

Let's determine angle b first

Angle b=20° (alternate angles)

Using cosine rule

Let the distance between the liner and the port be x

X² =8.8²+2.4²-2(8.8)(2.4)cos20

X²= 77.44 + 5.76-(39.69)

X²= 43.51

X= √43.51

X= 6.596

X= 6.6 miles

Let's determine the angles within the triangle using sine rule

2.4/sin b = 6.6/sin20

(2.4*sin20)/6.6= sin b

0.1244 = sin b

7.146= b°

Angle c= 180-20-7.146

Angle c= 152.854°

For the bearing

110+7.146= 117.146

180-117.146= 62.854°

Bearing= N 62.854°W

8 0
3 years ago
Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x
BaLLatris [955]

Answer:

The area of the region is 25,351 units^2.

Step-by-step explanation:

The Fundamental Theorem of Calculus:<em> if </em>f<em> is a continuous function on </em>[a,b]<em>, then</em>

                                   \int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) |  {_a^b}

where F is an antiderivative of f.

A function F is an antiderivative of the function f if

                                                    F^{'}(x)=f(x)

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x + 15 and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx

\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx

\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2

3 0
3 years ago
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