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Montano1993 [528]
2 years ago
11

Each of these labelled bags contains two apples.

Mathematics
1 answer:
Tems11 [23]2 years ago
3 0

Step-by-step explanation:

I just answered this.

the key is that ALL current labels are wrong. not "could be wrong", but "definitely wrong".

you need to pick an apple from the originally "red/green" labeled bag.

since that label is wrong, it must be one of the pure color bags.

so, that bag gets the label for the color that we picked.

now we look at the other 2 bags. they are both wrongly labeled, but there are only 2 options : the second color (which we did not use to label the first bag) and "red/green".

the bag with the color label we just assigned to our first bag must therefore get the second color label (if it were "red/green", it would mean that the third bag was actually correctly labeled, which was not the case), and the bag currently with the second color label is the actual "red/green" bag.

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Use the numbers listed to make the equation true<br><br> 2,6 and 5<br> __ + __ X_ = 16
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Due to the order of operations the correct answer is 6+2*5=16
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A group of 15 explorers to the south pole had just enough food to last them for 40 days how long would the food last if all of a
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Answer:

3 days

Step-by-step explanation:

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-2(x+1)-x+5 what do you think it is
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Need answer quickly! thank you in advance!
anyanavicka [17]

Answer:

b)(b²-a²)

Step-by-step explanation:

a cotθ + b cosecθ =p

b cotθ + a cosecθ =q

Now,

p²- q²

=(a cotθ + b cosecθ)² - (b cotθ + a cosecθ)²     [a²-b²=(a+b)(a-b)]

=(acotθ+bcosecθ + bcotθ+ acosecθ) (a cotθ + bcosecθ -bcotθ-acosecθ)

={a(cotθ+cosecθ)+b(cotθ+cosecθ)} {a (cotθ-cosecθ)+b (cosecθ-cotθ)}

={a(cotθ+cosecθ)+b(cotθ+cosecθ)} [a (cotθ-cosecθ) + {- b (cotθ-cosecθ)} ]

={a(cotθ+cosecθ)+b(cotθ+cosecθ)} {a (cotθ-cosecθ) - b (cotθ-cosecθ)}

={(cotθ+cosecθ)(a+b)} {(cotθ-cosecθ) (a-b)}

=(cotθ+cosecθ) (a+b) (cotθ-cosecθ) (a-b)

=(cotθ+cosecθ) (cotθ-cosecθ) (a+b) (a-b)        

= (cot²θ-cosec²θ) (a²-b²)                                 [(a+b) (a-b)= (a²-b²)]

= -1 . (a²-b²)                               [ 1+cot²θ=cosec²θ ; ∴cot²θ-cosec²θ=-1]

=(b²-a²)

6 0
4 years ago
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