To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Answer:
1.584
Step-by-step explanation:
1.584 = 3.96 × 0.4
Answer:
13 Boxes with $41 left over
Step-by-step explanation:
$600/$43 = 13.9 (so she can buy 13 boxes of light fixtures)
$43 x 13 = $559
$600-$559=$41 left over
Answer:
Ok
Step-by-step explanation:
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Answer:
y-7 = 4(x+9)
Step-by-step explanation:
Point slope form is
y-y1 = m(x-x1)
where m is the slope and (x1,y1) is the point
y-7 = 4(x--9)
y-7 = 4(x+9)
