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Elanso [62]
3 years ago
10

Please help quick please

Mathematics
2 answers:
Naya [18.7K]3 years ago
3 0

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: 9.27

Explanation:

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

const2013 [10]3 years ago
3 0

Answer:

9.27

You can find the answer by using the formula

r = √(V / (π * h)) ,

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Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x
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Answer:

The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is \mathbf{y=-\frac{2}{3}x+3 }

Step-by-step explanation:

We need to Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x

The equation in slope-intercept form is: y=mx+b where m is slope and b is y-intercept.

Finding Slope:

The both equations given are parallel. So, they have same slope.

Slope of given equation y= - 2/3x is m = -2/3

This equation is in slope-intercept form, comparing with general equation  y=mx+b where m is slope , we get the value of m= -2/3

So, slope of required line is: m = -2/3

Finding y-intercept

Using slope m = -2/3 and point (-3,5) we can find y-intercept

y=mx+b\\5=-\frac{2}{3}(-3)+b\\5=2+b\\ b=5-2\\b=3

So, we get b = 3

Now, the equation of required line:

having slope m = -2/3 and y-intercept b =3

y=mx+b\\y=-\frac{2}{3}x+3

The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is \mathbf{y=-\frac{2}{3}x+3 }

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