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Xelga [282]
2 years ago
14

True or false: The following lengths would be able to make a triangle: 5 in, 7 in, 3 in

Mathematics
1 answer:
lisov135 [29]2 years ago
7 0

Answer:

no

Step-by-step explanation:

cus its has to be 5. 5. 3 or something

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List the following numbers in order from least to greatest. a) 3.5× 10/3 B) 3.5× 10-2 C) 5.3 × 10/3
Crazy boy [7]

Answer:

3.5*10^{-2}, 3.5*10^3, 5.3*10^3

B, A, C

Step-by-step explanation:

This is scientific notation. The numbers 3.5 * 10^3\\3.5 *10^{-2}\\5.3 * 10^3 can be ordered least to greatest by looking at their digits and exponents. Since a -2 as an exponent is present, this means this is a small decimal and is the least. 3.5 and 5.3 have the same exponent of 3 but 5.3 is greater than 3.5 so its the greatest. The order is

3.5*10^{-2}, 3.5*10^3, 5.3*10^3

5 0
3 years ago
Kim buys a new shirt for $25.50. She has to pay 8% sales tax. How much tax will be paid?​
Ainat [17]
Tax she will pay would be $2.04
4 0
3 years ago
The radius of a cylinder is increased by 5 percent. Given that the height is constant, find the percentage increase in volume. ​
telo118 [61]

Step-by-step explanation:

Volume =pir^h

V1=pi r1^h

V2=pir2^2h

Now,V1/V2=r1^2/r2^2

v1/v2=r1^2/(1.05)^2 ((r2=r1+5/100r1)

v1/v2=1/1.1025

v1/v2=0.907

(v1/v2-1)=0.0907×100%

(v1-v2)/v2=9.07%

increase in volume is 9.07%

7 0
3 years ago
You must be at least 25 to rent a car ?
svlad2 [7]

Answer:

no, you have to be 18 or older

4 0
3 years ago
Read 2 more answers
The right end of a relaxed standard spring is at the origin; the left end is clamped at some point on the negative x-axis. Holdi
ella [17]

The work required to stretch the spring is 350J.

<h3>Hooke's Law</h3>

This law can be written by the formula: F=kx, where:

F= elastic force (N)

k= spring constant (N/m)

x= linear displacement (m)

<h3>Spring Work</h3>

For finding the spring work in J, you should apply the formula  W=\frac{k*(\Delta x)^2}{2}, where:

W= work (J)

k= spring constant (N/m)

x= difference between the linear displacements (m)

The question gives:

x=5 cm=0.05m requires a force of 1.4N

x=8 cm =0.08m

  • Step 1 - First, you should find the spring constant from Hooke's law, for x=5 cm and F=1.4N.

                                          F=kx\\ 1.4=k*0.05\\ \\ k=\frac{1.4}{0.05} =28\frac{N}{m}

  • Step 2 - Now you can apply the formula for spring work.

                                       W=\frac{k*(\Delta x)^2}{2}\\ \\ W=\frac{28*(8-3)^2}{2} \\ \\ W=\frac{28*(5)^2}{2}\\ \\  W=\frac{28*25}{2}\\ \\  W=\frac{700}{2}=350J

Read more about the spring work here:

brainly.com/question/3317535

5 0
3 years ago
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