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Xelga [282]
2 years ago
14

True or false: The following lengths would be able to make a triangle: 5 in, 7 in, 3 in

Mathematics
1 answer:
lisov135 [29]2 years ago
7 0

Answer:

no

Step-by-step explanation:

cus its has to be 5. 5. 3 or something

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Help please!!! A bag contains 50 marbles, 10 of which are blue, 8 are red, 20 are green, and 12 are purple. Marcie takes a marbl
Andru [333]

Answer:

A


Step-by-step explanation:

We would need to multiply the number of trials (which is 500) by the probability of choosing a red in 1 try from the information given.


<em>There are 50 in total, and 8 of them are red, so:</em>

P(red) = \frac{8}{50}=0.16


<em>Now we multiply this with 500 to get:</em>

500*0.16=80


The correct answer is A.

5 0
3 years ago
Read 2 more answers
Describe each step taken to solve the equation. Then, check the solution to see if it is valid. If it is not a valid solution, e
TEA [102]

Answer:

Step-by-step explanation:

given,

a) √x + 6 = 4                                                    

to solve the above equation subtract both side with 6

    √x + 6 - 6  = 4 - 6                  

                √x  = -2                  

squaring both side

                (√x)² = (-2)²              

                       x = 4            

a) ∛x + 6 = 4                                            

to solve the above equation subtract both side with 6

    ∛x + 6 - 6  = 4 - 6

                ∛x  = -2

cubing  both side

                (√x)³ = (-2)³

                      x = -8

4 0
3 years ago
Write an equation for the both term of the arithmetic sequence 30,26,22,18
balandron [24]

Answer:

I guess it decreases by 4 everytime so -4??? If thats what your asking

Step-by-step explanation:

30,26,22,18,14,10,8,4,-2.

6 0
3 years ago
1. cot x sec4x = cot x + 2 tan x + tan3x
Mars2501 [29]
1. cot(x)sec⁴(x) = cot(x) + 2tan(x) + tan(3x)
    cot(x)sec⁴(x)            cot(x)sec⁴(x)
                   0 = cos⁴(x) + 2cos⁴(x)tan²(x) - cos⁴(x)tan⁴(x)
                   0 = cos⁴(x)[1] + cos⁴(x)[2tan²(x)] + cos⁴(x)[tan⁴(x)]
                   0 = cos⁴(x)[1 + 2tan²(x) + tan⁴(x)]
                   0 = cos⁴(x)[1 + tan²(x) + tan²(x) + tan⁴(4)]
                   0 = cos⁴(x)[1(1) + 1(tan²(x)) + tan²(x)(1) + tan²(x)(tan²(x)]
                   0 = cos⁴(x)[1(1 + tan²(x)) + tan²(x)(1 + tan²(x))]
                   0 = cos⁴(x)(1 + tan²(x))(1 + tan²(x))
                   0 = cos⁴(x)(1 + tan²(x))²
                   0 = cos⁴(x)        or         0 = (1 + tan²(x))²
                ⁴√0 = ⁴√cos⁴(x)      or      √0 = (√1 + tan²(x))²
                   0 = cos(x)         or         0 = 1 + tan²(x)
         cos⁻¹(0) = cos⁻¹(cos(x))    or   -1 = tan²(x)
                 90 = x           or            √-1 = √tan²(x)
                                                         i = tan(x)
                                                      (No Solution)

2. sin(x)[tan(x)cos(x) - cot(x)cos(x)] = 1 - 2cos²(x)
              sin(x)[sin(x) - cos(x)cot(x)] = 1 - cos²(x) - cos²(x)
   sin(x)[sin(x)] - sin(x)[cos(x)cot(x)] = sin²(x) - cos²(x)
                               sin²(x) - cos²(x) = sin²(x) - cos²(x)
                                         + cos²(x)              + cos²(x)
                                             sin²(x) = sin²(x)
                                           - sin²(x)  - sin²(x)
                                                     0 = 0

3. 1 + sec²(x)sin²(x) = sec²(x)
           sec²(x)             sec²(x)
      cos²(x) + sin²(x) = 1
                    cos²(x) = 1 - sin²(x)
                  √cos²(x) = √(1 - sin²(x))
                     cos(x) = √(1 - sin²(x))
               cos⁻¹(cos(x)) = cos⁻¹(√1 - sin²(x))
                                 x = 0

4. -tan²(x) + sec²(x) = 1
               -1               -1
      tan²(x) - sec²(x) = -1
                    tan²(x) = -1 + sec²
                  √tan²(x) = √(-1 + sec²(x))
                     tan(x) = √(-1 + sec²(x))
            tan⁻¹(tan(x)) = tan⁻¹(√(-1 + sec²(x))
                             x = 0
5 0
3 years ago
Write the equation g(x) of the transformation of the parent graph f(x) = |x| translated right 5 units.
Archy [21]

Answer:

g(x) = |x-5|

Step-by-step explanation:

f(x) = |x|

y = f(x + C)  C < 0 moves it right

g(x) = |x-5| moves it to the right 5 units

7 0
3 years ago
Read 2 more answers
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