Locate fractions greater than 1 on a number line

1 answer:

6 0

1/3, 1/4, 1/100, 1/24567, 1/278, 1234567/1456790 There's infinitely many fractions above 1 take any number as the numerator and have a bigger number as the denominator put it after one on the graph.

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Solve the proportions, Where necessary, round to the nearest hundreths

Sophie [7]

9/ 10 = X /10

multiply each side by 10

9 = x

Choice A

4 0

2 years ago

I need to know how to solve <br> -4-(2+4(-6)-4-(2^2-5*2))

sweet-ann [11.9K]

Answer:

Step-by-step explanation:

This problem requires PEMDAS

Parentheses ( )

Exponents ^

Multiplication

Division

Add

Subtract

Start by solving anything in parentheses. There's an exponent within the parentheses, so we change that 2^2 into 4 and also make sure to multiply 5 x 2 before subtracting.

-4 - (2 + -24 - 4 - (4-10))

-4 - (2 + -24 - 4 - (-6))

Again, solve parentheses first.

-4 - (-22 - 4 - (-6))

-4 - (-26 + 6)

-4 - (-20)

-4 + 20

Answer is 16

4 0

2 years ago

In which quadrants do solutions for the inequality y is less than or equal to two sevenths times x plus 1 exist?

hram777 [196]

Answer:

y will be in every single quadrant

Step-by-step explanation:

So we have the equation $y\leq \frac{2}{7} x+1$ first we will have to look at the equation. It says that y is less than or equal to $\frac{2}{7} x+1$ since y is less than $\frac{2}{7} x+1$ the only place the shaded area where y can be is under the line that is drawn be the equation. When the equation is graphed the y-intercept will be on positive 1 it since slope is rise over run it will look something like the file attached to this. so under the line you can see every single quadrant so that is why it would be that way