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Kruka [31]
2 years ago
12

What is the y-intercept, axis of symmetry and vertex of the following function.

Mathematics
1 answer:
pshichka [43]2 years ago
6 0
The y intercept is always c (-5) and to the axis of symmetry u do -b/2a which is -1 and the vertex is (-1,10) because u pug in -1 into the equation. lmk if it’s right!
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Step-by-step explanation:

The x intercepts are the values of x when y = 0 ie the roots of the equation
-x^2 -x +12 = 0

or

x^2  + x  - 12 = 0

We can re-write the above as:
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This gives the two roots as x = -4 and x = +3. Leftmost (smallest) root is -4 and rightmost(largest) root is +3

y intercept is when x = 0. Plugging into the original equation, y value at x = 0 is 12

Vertex x value is given by the formula -b/2a where a is the coefficient of x^2 and b the coefficient of x

Here a = -1, b= -1 so vertex x value = - (-1)/(-1).2 = - 1/2 = -0.5

Plugging this value of x into the original function gives the vertex y value
y = - (0.5^{2}) - (-0.5) + 12\\= -0.25 + 0.5 + 12 = 12.25

The line of symmetry is the vertical line corresponding to the vertex x value so line of symmetry is at x = -0.5

The graph of the quadratic function shows these values

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