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NeX [460]
2 years ago
15

The tree diagram represents an experiment consisting of two trials. P(D) = [? ]

Mathematics
1 answer:
joja [24]2 years ago
5 0

Answer:

9 over 11 plus 8 over 12 = 2.7

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If f(x) = 3x + 10x and g(x) = 4x - 2, find (f + g)(x).
lubasha [3.4K]

Answer: If you are solving the Function Operation, the answer will be 17x-2.

Step-by-step explanation: Use the given functions to set up and simplify (f+g)(x).

Hope this helps you out. If not, comment and let me know what you are looking for/needing/wanting. Good luck, mate! ☺

7 0
3 years ago
Read 2 more answers
At the beginning of the school year, the 7th grade class at Oak Hill Middle School has 480 students. There are 270 girls and 210
Dimas [21]

Answer:

Part 1: 43.75%

Part 2: 44.07%

Step-by-step explanation:

Hello!

(Pt.1) First, set up a ratio 210/480. Next, you use long division I got the percent 43.75. After that, you subtract 6 from the girls group, (because of them moving away and then more coming back.) and 2 from the boys group. Then, you subtract those from the school "population" and you get 472 as the final population. So then you set up another ratio, 208/472. I got a percent of 44.07% from that.

Thanks For Reading!

7 0
2 years ago
Mandy has $20 in a savings account the interest rate is 10% per year and is not compounded. how much will she have in one year.
sveta [45]
She will have $22

P       R     T
20 x 1.1 x 1 
22

6 0
3 years ago
The graph of the quadratic function y = ax^2 + bx + c is given.<br> Find a + b + c.
andrey2020 [161]

Answer:

\frac{145}{24}\approx 6***

Answers may vary depending on the person reading the graph.

It is hard to tell what they think crosses nicely.

For example, I decided that the graph crossed nicely at the following points:

(0,3)

(2,8)

(6,5)

Step-by-step explanation:

I see that the graph crosses at (0,3),(2,8), and (6,5).

The equation y=ax^2+bx+c tells us the y-intercept is c since when x=0 we have y=a(0)^2+b(0)+c=0+0+c=c.

The y-intercept for our graph is 3. Therefore, c=3.

So far we have the equation:

y=ax^2+bx+3.

Let's enter the other points creating a system of linear equations to solve:

8=a(2)^2+b(2)+3

5=a(6)^2+b(6)+3

Let's simplify:

8=4a+2b+3

5=36a+6b+3

Let's subtract 3 on both sides:

5=4a+2b

2=36a+6b

I choose to solve the system by elimination.

Let's multiply the top equation by -3:

-15=-12a-6b

2=36a+6b

Now adding the equations results in:

-13=24a

Divide both sides by 24:

\frac{-13}{24}=a

Now using one of the equations we can find b:

5=4a+2b with a=\frac{-13}{24}

5=4\frac{-13}{24}+2b

5=\frac{-13}{6}+2b

Add 13/6 on both sides:

5+\frac{13}{6}=2b

\frac{30+13}{6}=2b

\frac{43}{6}=2b

Divide both sides by 2:

\frac{43}{2(6)}=b

\frac{43}{12}=b

So we have the equation:

y=\frac{-13}{24}x^2+\frac{43}{12}+3

Let's evaluate a+b+c now:

\frac{-13}{24}+\frac{43}{12}+3

\frac{-13+86+72}{24}

\frac{73+72}{24}

\frac{145}{24}

4 0
3 years ago
Suppose a system of two linear equations has one solution. What must be true about the graphs of the two equations?
malfutka [58]
They should both have the same solution?
8 0
2 years ago
Read 2 more answers
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