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2 years ago

15

The tree diagram represents an experiment consisting of two trials. P(D) = [? ]

1 answer:

joja [24]2 years ago

5 0

Answer:

9 over 11 plus 8 over 12 = 2.7

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If f(x) = 3x + 10x and g(x) = 4x - 2, find (f + g)(x).

lubasha [3.4K]

Answer: If you are solving the Function Operation, the answer will be 17x-2.

Step-by-step explanation: Use the given functions to set up and simplify (f+g)(x).

Hope this helps you out. If not, comment and let me know what you are looking for/needing/wanting. Good luck, mate! ☺

7 0

3 years ago

Read 2 more answers

At the beginning of the school year, the 7th grade class at Oak Hill Middle School has 480 students. There are 270 girls and 210

Dimas [21]

Answer:

Part 1: 43.75%

Part 2: 44.07%

Step-by-step explanation:

Hello!

(Pt.1) First, set up a ratio $210/480$ . Next, you use long division I got the percent 43.75. After that, you subtract 6 from the girls group, (because of them moving away and then more coming back.) and 2 from the boys group. Then, you subtract those from the school "population" and you get 472 as the final population. So then you set up another ratio, $208/472$ . I got a percent of 44.07% from that.

Thanks For Reading!

7 0

2 years ago

Mandy has $20 in a savings account the interest rate is 10% per year and is not compounded. how much will she have in one year.

sveta [45]

She will have $22

P R T
20 x 1.1 x 1
22

6 0

3 years ago

The graph of the quadratic function y = ax^2 + bx + c is given.<br> Find a + b + c.

andrey2020 [161]

Answer:

$\frac{145}{24}\approx 6$ ***

Answers may vary depending on the person reading the graph.

It is hard to tell what they think crosses nicely.

For example, I decided that the graph crossed nicely at the following points:

$(0,3)$

$(2,8)$

$(6,5)$

Step-by-step explanation:

I see that the graph crosses at $(0,3)$ , $(2,8)$ , and $(6,5)$ .

The equation $y=ax^2+bx+c$ tells us the $y$ -intercept is $c$ since when $x=0$ we have $y=a(0)^2+b(0)+c=0+0+c=c$ .

The $y$ -intercept for our graph is $3$ . Therefore, $c=3$ .

So far we have the equation:

$y=ax^2+bx+3$ .

Let's enter the other points creating a system of linear equations to solve:

$8=a(2)^2+b(2)+3$

$5=a(6)^2+b(6)+3$

Let's simplify:

$8=4a+2b+3$

$5=36a+6b+3$

Let's subtract 3 on both sides:

$5=4a+2b$

$2=36a+6b$

I choose to solve the system by elimination.

Let's multiply the top equation by -3:

$-15=-12a-6b$

$2=36a+6b$

Now adding the equations results in:

$-13=24a$

Divide both sides by 24:

$\frac{-13}{24}=a$

Now using one of the equations we can find $b$ :

$5=4a+2b$ with $a=\frac{-13}{24}$

$5=4\frac{-13}{24}+2b$

$5=\frac{-13}{6}+2b$

Add 13/6 on both sides:

$5+\frac{13}{6}=2b$

$\frac{30+13}{6}=2b$

$\frac{43}{6}=2b$

Divide both sides by 2:

$\frac{43}{2(6)}=b$

$\frac{43}{12}=b$

So we have the equation:

$y=\frac{-13}{24}x^2+\frac{43}{12}+3$

Let's evaluate $a+b+c$ now:

$\frac{-13}{24}+\frac{43}{12}+3$

$\frac{-13+86+72}{24}$

$\frac{73+72}{24}$

$\frac{145}{24}$

4 0

3 years ago

Suppose a system of two linear equations has one solution. What must be true about the graphs of the two equations?

malfutka [58]

They should both have the same solution?

8 0

2 years ago

Read 2 more answers