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Annette [7]
3 years ago
14

Sasha is cutting a cake into 42 equal-sized pieces. If 14 people want cake, then they can each have 3 slices. And if 21 people w

ant cake, then they can each have 2 slices. What is the constant of proportionality in this inverse variation?
Mathematics
1 answer:
kupik [55]3 years ago
4 0

Answer:

k = 42

the constant of proportionality in this inverse variation is 42.

Step-by-step explanation:

Let x represent the number of people that want cake

And y the number of slices each can have;

Since x is inversely proportional to y;

x = k/y .....1

Where k is the proportionality constant;

To solve for k, we will substitute any of the case scenario given into equation 1.

If 14 people want cake, then they can each have 3 slices;

x = 14 , y = 3

substituting;

14 = k/3

k = 14 × 3 = 42

k = 42

the constant of proportionality in this inverse variation is 42.

Therefore,

x = 42/y

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Put y + 3 = -3(x + 2) in slope-intercept form.
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3 years ago
Read 2 more answers
If you can answer this, please help !
PolarNik [594]

Answer:

the total of angle's in traingle is 180

so 85+53+c=180

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8 0
2 years ago
Read 2 more answers
PLEASE HELP ASAP! I don’t recall how to do this!
MakcuM [25]

Answer:

Step-by-step explanation:

For a. we start by dividing both sides by 200:

(1.05)^x=1.885

In order to solve for x, we have to get it out from its position of an exponent.  Do that by taking the natural log of both sides:

ln(1.05)^x=ln(1.885)

Applying the power rule for logs lets us now bring down the x in front of the ln:

x * ln(1.05) = ln(1.885)

Now we can divide both sides by ln(1.05) to solve for x:

x=\frac{ln(1.885)}{ln(1.05)}

Do this on your calculator to find that

x = 12.99294297

For b. we will first apply the rule for "undoing" the addition of logs by multipllying:

ln(x*x^2)=5

Simplifying gives you

ln(x^3)=5

Applying the power rule allows us to bring down the 3 in front of the ln:

3 * ln(x) = 5

Now we can divide both sides by 3 to get

ln(x)=\frac{5}{3}

Take the inverse ln by raising each side to e:

e^{ln(x)}=e^{\frac{5}{3}}

The "e" and the ln on the left undo each other, leaving you with just x; and raising e to the power or 5/3 gives you that

x = 5.29449005

For c. begin by dividing both sides by 20 to get:

\frac{1}{2}=e^{.1x}

"Undo" that e by taking the ln of both sides:

ln(.5)=ln(e^{.1x})

When the ln and the e undo each other on the right you're left with just .1x; on the left we have, from our calculators:

-.6931471806 = .1x

x = -6.931471806

Question d. is a bit more complicated than the others.  Begin by turning the base of 4 into a base of 2 so they are "like" in a sense:

(2^2)^x-6(2)^x=-8

Now we will bring over the -8 by adding:

(2^2)^x-6(2)^x+8=0

We can turn this into a quadratic of sorts and factor it, but we have to use a u substitution.  Let's let u=2^x

When we do that, we can rewrite the polynomial as

u^2-6u+8=0

This factors very nicely into u = 4 and u = 2

But don't forget the substitution that we made earlier to make this easy to factor.  Now we have to put it back in:

2^x=4,2^x=2

For the first solution, we will change the base of 4 into a 2 again like we did in the beginning:

2^2=2^x

Now that the bases are the same, we can say that

x = 2

For the second solution, we will raise the 2 on the right to a power of 1 to get:

2^x=2^1

Now that the bases are the same, we can say that

x = 1

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3 years ago
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