The present age of father is 86 years old and present age of son is 48 years old
<em><u>Solution:</u></em>
Given that, a father is now 38 years older than his son
Ten years ago he was twice as old as his son
Let "x" be the age of son now
Therefore, from given,
Father age now = 38 + age of son now
Father age now = 38 + x
<em><u>Ten years ago he was twice as old as his son</u></em>
Age of son ten years ago = age of son now - 10
Age of son ten years ago = x - 10
Age of father ten years ago = 38 + x - 10
Then we get,
Age of father ten years ago = twice the age of son ten years ago
38 + x - 10 = 2(x - 10)
28 + x = 2x - 20
2x - x = 28 + 20
x = 48
Thus son age now is 48 years old
Father age now = x + 38 = 48 + 38 = 86
Thus present age of father is 86 years old and present age of son is 48 years old
Answer:
58.33%
Step-by-step explanation:
is %
-------- = ---------
of 100
Just plug in the numbers based on what it tells you.
What % = goes in the % spot
of 60 = goes in the of spot
is 35 = goes in the is spot
35 x
--------- = ---------
60 100
Cross multiply:
60 * x = 60x 35 * 100 = 3500
60x = 3500
Divide by 60 to get x by itself.
3500 / 60 = 58.33
Put the percent sign after it:
58.33%
I hope this helps.
You're looking for a value

such that

Because the distribution is symmetric, the value of

in either case will be the same.
Now, because the distribution is continuous, you have that

The mean for the standard normal distribution is

, and because the distribution is symmetric about its mean, it follows that

.

You can consult a

score table to find the corresponding score for this probability. It turns out to be

.
Answer:
x=-5/6
Step-by-step explanation: