Answer:
Two consecutive numbers whose squares differ by 33 are 16 and 17
Step-by-step explanation:
lets assume first number be x
since numbers are consecutive , so other number will be x + 1
From given information in question
(x + 1)² - x² = 33
⇒ (x² + 1² + 2x) - x² = 33 [ since (a+b)² = a² + b² + 2ab ]
⇒ x² + 1² + 2x - x² = 33
⇒ 2x + 1 = 33
⇒ 2x = 33 - 1
⇒ x = 32/2 = 16
so one number is x = 16 and other number is x + 1 = 16 + 1 = 17
lets recheck our solution
17² - 16² = 289 - 256 = 33 , And since difference is 33 , two required consecutive numbers are 16 and 17.
50% - .5
7/15 - .46
the remote control car
Use log definition: if logₐ(b) = c then b = a^c
log₃(x) = 6 → x = 3⁶
x = 3⁶ → x = 726
Therefore, x = 726
Best of Luck!
The carrot patch is a 2 by 5 rectangle so 2 times 5 is 10 so the answer is A
<span> x^2 - 16 </span><span>x^3 - 2x^2+x
</span><span> ------------- * ---------------------
2x+8 </span><span>x^2 + 3x -4
</span><span>
(x+4)(x-4) x (x - 1)(x - 1)
= ----------------- * ----------------------
2(x+4) (x + 4)(x - 1)
</span> x(x- 4) (x - 1)
= -----------------
2 (x + 4)
