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2 years ago

Can you simplify 37/80

Mathematics

1 answer:

Setler [38]2 years ago

7 0

Answer:

Step-by-step explanation:

37 is prime, so it's not possible to reduce/simplify 37/80. 37/80 is the ratio of two integers. We could, of course, use a calculator to find the decimal equivalent: 0.4625, but this is not more accurate than the ratio 37/80.

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What is 0.080 as a fraction

nordsb [41]

That is 8/100 or 80/1000

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3 years ago

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In the data set below, what are the lower quartile, the median, and the upper quartile?

ivolga24 [154]

Answer:

its 55

Step-by-step explanation:

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3 years ago

Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +

GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3) ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2) ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)

On solving above equation for x

(x+6) (x+3) =2(x+3) (2x+2)

x+6 = 4x + 4

x-4x = 4 – 6

x = $\frac{2}{3}$

Dimension of pool A

Length = x+6 = ( $\frac{2}{3}$ ) +6 = 6.667m

Width = x +3 = ( $\frac{2}{3}$ ) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2( $\frac{2}{3}$ ) + 6 = $\frac{22}{3}$ = 7.333m

Width = 2x + 2 = 2( $\frac{2}{3}$ ) + 2 = $\frac{10}{3}$ = 3.333m

Verifying the area:

Area of pool A = ( $\frac{20}{3}$ ) x ( $\frac{11}{3}$ ) = $\frac{220}{9}$ = 24.44 meter

Area of pool B = ( $\frac{22}{3}$ ) x ( $\frac{10}{3}$ ) = $\frac{220}{9}$ = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0

3 years ago

Jorge wrote the inequality -12°F < -3°F to compare the temperature at 9 A.M. And 9 P.M. It was colder at 9 P.M. than at 9 A.M

Lady_Fox [76]

-3f is the temperature at 9am because -12f is colder than -3f

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3 years ago

Suppose a basketball player has made 291 out of 389 free throws. If the player makes the next 2 free throws, I will pay you $38.

VMariaS [17]

Answer:

The expected value of the proposition is -$0.76.

Step-by-step explanation:

It is provided that a basketball player has made 291 out of 389 free throws.

Then rate of him making a free throw is,

$P(\text{free throw})=\frac{291}{389}=0.7481$

The probability that he makes the next 2 free throws is:

$P(\text{Next 2 free throws})=(0.7481)^{2}=0.5596$

The payout rules are:

If the player makes the next 2 free throws, I will pay you $38.
Otherwise you pay me $50.

Compute the expected value of the proposition as follows:

Expected value = $38 × P (Makes both) + (-$50) × P (Misses both)

$=($38\times 0.5596)+(-$50\times (1-0.5596))\\=21.2648-22.02\\=-0.7552\\\approx -$0.76$

Thus, the expected value of the proposition is -$0.76.

5 0

3 years ago