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3 years ago

8

Simplify the equations below

1 answer:

IRISSAK [1]3 years ago

5 0

Number 2 is 4x^5/3y^5 and 14 is 3125x^10

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Which of the following equations has the same solutions as the equation 3x + 2y = -12? Check all that apply.

Mariulka [41]

Answer:

$B.\ -3x - 2y = 12$

$C.\ 15x + 10y = -60$

$E.\ 6x + 4y = -24$

$F.\ 1.5x + y =-6$

Step-by-step explanation:

Given

$3x + 2y = -12$

Required

Determine equations with same solution as $3x + 2y = -12$

For a solution to have the same solution as $3x + 2y = -12$ , the equation must be expressed as $3x + 2y = -12$

$A.\ 3x - 2y = 12$

This can not be expressed as $3x + 2y = -12$

$B.\ -3x - 2y = 12$

Multiply through by -1

$-1(-3x - 2y) = 12 * -1$

$3x + 2y = -12$

This has the same solution as the given equation

$C.\ 15x + 10y = -60$

Divide through by 5

$\frac{15x}{5} + \frac{10y}{5} = \frac{-60}{5}$

$3x + 2y = -12$

This has the same solution as the given equation

$D.\ 6x + 2y = -12$

Divide through by 2

$\frac{6x}{2} + \frac{2y}{2} = \frac{-12}{2}$

$3x + y = -6$

This can not be expressed as $3x + 2y = -12$

$E.\ 6x + 4y = -24$

Divide through by 2

$\frac{6x}{2} + \frac{4y}{2} = \frac{-24}{2}$

$3x + 2y = -12$

This has the same solution as the given equation

$F.\ 1.5x + y =-6$

Multiply through by 2

$2*1.5x + 2*y =-6*2$

$3x + 2y =-12$

This has the same solution as the given equation

$G.\ x + \frac{2}{3}y = -12$

Multiply through by 3

$3 * x + 3*\frac{2}{3}y = -12*3$

$3x + 2y = -36$

This can not be expressed as $3x + 2y = -12$

The equations with the same solution as $3x + 2y = -12$ are the ones that we were able to expressed as $3x + 2y = -12$ .

And the equations are:

$B.\ -3x - 2y = 12$

$C.\ 15x + 10y = -60$

$E.\ 6x + 4y = -24$

$F.\ 1.5x + y =-6$

7 0

3 years ago

Which one represents the problem

timama [110]

Answer:

$\frac{1}{3} \div \: 4$

3 0

3 years ago

Read 2 more answers

PLEASE HELP ILL GIVE BRAINLYEST

posledela

A is the correct answer

3 0

4 years ago

Read 2 more answers

4/5 + 2/3 in simplest terms

RSB [31]

Answer:

$\frac{8}{15}$

Step-by-step explanation:

1) use this rule: $\frac{a}{b}$ × $\frac{c}{d} =\frac{ac}{bd}$

$\frac{4*2}{5*3}$

2) simplify 4 * 2 to 8

$\frac{8}{5*3}$

3) simplify 5 * 3 to 15

$\frac{8}{15}$

8 0

2 years ago

If the area of the blue square is 144 units2 and the area of the pink square is 1225 units2, then the length of the hypotenuse i

navik [9.2K]

Answer: 37 units

Step-by-step explanation:

$Blue=144units^2$ This also works as the height of the triangle.

$Pink=1225units^2$ This also works as the base of the triangle.

Let's call pink ''a'', and blue ''b''. The side we're looking for ''c'' is the hypothenuse.

To find the values of a and b, use the area formula of a square and solve for a side. In this case, since we're going to need the squared values, this step can be omitted.

$Formula: A=s^2$

$s=\sqrt[]{A}$

Let's work with Blue.

$s=\sqrt[]{144units^2} \\s=12units$

Now Pink.

$s=\sqrt[]{1225units^2}\\s=35units$

So we have a triangle with a base of 35 units and a height of 12 units.

Now let's use the pythagoream's theorem to solve.

$c^2=a^2+b^2\\c=\sqrt[]{a^2+b^2} \\c=\sqrt[]{(12units)^2+(35units)^2}\\c=\sqrt[]{144units^2+1225units^2}\\ c=\sqrt[]{1369units^2}\\ c=37units$

7 0

3 years ago