Question

I need help please find the 7th term 3, 1,1/3

Answer 1

The sequence 3, 1,1/3 is a geometric sequence

The 7th term of the sequence is 1/243

How to determine the 7th term?

The sequence is given as:

3, 1,1/3

The above sequence is a geometric sequence with the following parameters:

• First term, a= 3
• Common ratio, r = 1/3

The nth term is then calculated as:

Tn = ar^(n-1)

So, the 7th term is:

T7 = ar^6

Substitute known values

T7 = 3 * (1/3)^6

This gives

T7 = 1/3^5

Evaluate

T7 = 1/243

Hence, the 7th term of the sequence is 1/243

Read more about geometric sequence at:

brainly.com/question/24643676