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Goshia [24]
2 years ago
11

Help me answer this now.​

Mathematics
2 answers:
aalyn [17]2 years ago
3 0

x + 2x + 6 = 27

3x + 6 = 27

x + 2 = 9

x = 9 - 2

x = 7

2 × 7 = 14

14 + 6 = 20

ycow [4]2 years ago
3 0
Use phot math, it answers that
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How many sites are show in this data set?
andre [41]

Answer:

The total number of sites are 15 .

Step-by-step explanation:

As shown in question.

The number of sites in 2 shield darter = 3

The number of sites in 3 shield darter = 1

The number of sites in 4 shield darter = 4

The number of sites in 6 shield darter = 2

The number of sites in 7 shield darter = 3

The number of sites in 8 shield darter = 1

The number of sites in 9 shield darter = 1

Thus

Total number of sites =  Number of sites in 2 shield darter + Number of sites in 3 shield darter +  Number of sites in 4 shield darter +  Number of sites in 6 shield darter +  Number of sites in 7 shield darter  +  Number of sites in 8 shield darter + Number of sites in 9 shield darter

Putting the values in above

                                  = 3 + 1 + 4 + 2 + 3 + 1 +1

                                  = 15

Therefore the total number of sites are 15 .

3 0
3 years ago
Can some one help me plsss!!?
Dahasolnce [82]
Ha uuuu un día y que ha dado la oportunidad para el teléfono
3 0
2 years ago
Whats the awnser to the image that is selected?????
VikaD [51]

Answer:

30 units

Step-by-step explanation:

In order to find the length of the 3rd side of the triangle, the hypotenuse, you can use the Pythagorean Theorem. Using this method, you get 5^2+12^2=169. The square root of 169 is 13.

5 + 12 + 13 = 30 units.

7 0
2 years ago
Harry worked the following hours in a week. What are the average hours worked for these five days?
Yuki888 [10]
Add all of the hours together than divide by 5 should get 40
4 0
3 years ago
Read 2 more answers
After being rearranged and simplified, which of the following equations could be solved using the quadratic formula?
dmitriy555 [2]
A. 2x^2 - 3x + 10 = 2x + 21
2x^2 - 3x - 2x + 10 - 21 = 0
2x^2 - 5x - 11 = 0                              (quadratic equation)

2x^2 - 6x - 7 = 2x^2
2x^2 - 2x^2 - 6x - 7 = 0
-6x - 7 = 0                                          (not a quadratic equation)

5x^2 + 2x - 4 = 2x^2
5x^2 - 2x^2 + 2x - 4 = 0
3x^2 + 2x - 4                                      (quadratic equation)

5x^3 - 3x + 10 = 2x^2
5x^3 - 2x^2 - 3x + 10 = 0                    (not a quadratic equation)

Therefore, options a and c can be solved using the quadratic formula.
3 0
3 years ago
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