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3 years ago

Use compatible numbers to find two estimates for 42 divided by 396

1 answer:

7 0

42 ÷ 396
You could use 40 ÷ 400, which would give you 0.1 as an estimate.
You could also use 42 ÷ 420, which would also give you 0.1 as an estimate.

By the way, by a pair of "compatible numbers", it means when you can easily work out the sum by calculating the first digits multiplied or divided together, then add the zeros.

For example, with 40 ÷ 400, we know that
40 ÷ 40 is 1, so we just put the other 0 infront of the decimal point to make it 0.1.

If it was multiplying (2 x 600), you could work out 2 x 6 (12), then add the 0's to get 1,200

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3 years ago

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Find the distance between the complex numbers. z1 = 9 - 9i z2 = 10 - 9i

steposvetlana [31]

Answer:

The distance between the two given complex numbers = 9

Step-by-step explanation:

Explanation:-

Step(i):-

Given Z₁ = 9 - 9 i and Z₂ = 10 -9 i

Let A and B represent complex numbers Z₁ and Z₂ respectively on the argand plane

⇒ A = Z₁ = x₁ +i y₁ = 9 - 9 i and

B = Z₂ = x₂+ i y₂ = 10 -9 i

Let (x₁ , y₁) = ( 9, -9)

(x₂, y₂) = (10, -9)

Step(ii):-

The distance between the two points are

A B = $\sqrt{(x_{2} - x_{1})^{2}+(y_{2} - y_{1})^{2} }$

A B = $\sqrt{(10 - 1)^{2}+(-9 - (-9))^{2} }$

AB = $\sqrt{(9)^{2} +(-9+9)^{2} }$

AB = √81 = 9

Conclusion:-

The distance between the two given complex numbers = 9

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2 years ago

Factor this for me please!

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$\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
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r=-4
\end{cases}\implies a_n=-2(-4)^{n-1}$

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